A triangle has sides with lengths of 3 yards, 4 yards, and 5 yards. Is it a right triangle?

Mathematics

2 answers:

yulyashka [42]3 years ago

7 0

Answer:

It is a right triangle

Step-by-step explanation:

Depending on how you make the triangle if 3 is A 4 is B and 5 is C then the Pythagorean Theorm would be correct and it would be a right triangle.

SpyIntel [72]3 years ago

3 0

Answer:

A triangle has sides with lengths of 6 inches, 8 inches, and 10 inches. Is it a right triangle?

Step-by-step explanation:

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Solve the equation 4=t/2.5

larisa [96]

the answer would be 10 because you have to times by 2.5 on both sides to get t on its own.

4 × 2.5 is 10

6 0

3 years ago

Read 2 more answers

What is the coefficient of the x^5y^5- term in the biomial expansion of (2x-3y)^10

jasenka [17]

<u>Answer:</u>

The coefficient of $x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552$

<u>Solution: </u>

The given expression is $(2 x-3 y)^{10}$

As per binomial theorem, we know,

$(x+y)^{n}=\sum n C_{k} x^{n-k} y^{k}$

Now here a = 2x, b = (- 3y) and n = 10 and k = 0,1,2,….10

Now $x^{5}\times y^5$ will be the 6 term where k =5

Now, $\mathrm{T}_{6}=10 \mathrm{C}_{5} \times(2 \mathrm{x})^{(10-5)} \times(-3 \mathrm{y})^{5}=10 \mathrm{C}_{5} 2^{5} \times \mathrm{x}^{5} \times(-3)^{5} \times \mathrm{y}^{5}$

So, the coefficient of $x^{5} \times y^{5} \text { is }=10\left(5 \times 2^{5} \times(-3)^{5}\right$ .

$10 \mathrm{C}_{5}=\frac{10 !}{5 ! \times(10-5) !}=\frac{10 !}{5 !+5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 !}{5 ! \times 5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1}=\left(\frac{30240}{120}\right)=252$