Question

Can Someone PleasePLEASE Help?? I'm lost.

Answer 1

$\bf a_1=-2\qquad a_n=3\cdot a_{n-1}\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term}\\ r=\textit{common ratio}\\ -------\\ n=6\\ a_1=-2\\ r=3 \end{cases} \\\\\\ a_n=a_1\cdot r^{n-1}\implies a_6=(-2)(3^{6-1})$

notice, the notation is just saying, that 3 * "the previous term, or n-1" is the next term, thus the common ratio, or multiplier is 3