According to the use of binomial expansion, the approximate value of √3 is found by applying the infinite sum √3 = 1 + (1 /2) · 2 - (1 / 8) · 2² + (1 / 16) · 2³ - (5 / 128) · 2⁴ + (7 / 256) · 2⁵ - (21 / 1024) · 2⁶ + (33 / 2048) · 2⁷ - (429 / 32768) · 2⁸ +...
An acceptable result cannot be found manually for it requires a <em>high</em> number of elements, with the help of a solver we find that the <em>approximate</em> value of √3 is 1.732.
<h3>How to approximate the value of a irrational number by binomial theorem</h3>
Binomial theorem offers a formula to find the <em>analytical</em> form of the power of a binomial of the form (a + b)ⁿ:
(1)
Where:
- a, b - Constants of the binomial.
- n - Grade of the power binomial.
- k - Index of the k-th element of the power binomial.
If we know that a = 1, b = 2 and n = 1 / 2, then an approximate expression for the square root is:
√3 = 1 + (1 /2) · 2 - (1 / 8) · 2² + (1 / 16) · 2³ - (5 / 128) · 2⁴ + (7 / 256) · 2⁵ - (21 / 1024) · 2⁶ + (33 / 2048) · 2⁷ - (429 / 32768) · 2⁸ +...
To learn more on binomial expansions: brainly.com/question/12249986
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Answer:
A'(-1, -1)
Step-by-step explanation:
Dilation about the origin multiplies each individual coordinate value by the dilation factor.
A' = (1/3)A = (1/3)(-3, -3) = (-1, -1)
Answer:
4 
Step-by-step explanation:
Answer:
real:√2, 3,-1, 1/2 etc
natural: 1,2,3,4,5,6.....(0 is not included)
integers:. .............-4,-3,-2,-1,0,1,2,3,4........ etc
rational: nos. which are in p/q form
:1/2,3/4,4/9 etc
irrational: nos. which cannot be written in p/q form
: √2,√3... etc
irrational: √2, √3, √5, √11, √21, π(Pi)