3 years ago

Find the distance between the points J(−8, 0) and K(1, 4).

Mathematics

2 answers:

xxMikexx [17]3 years ago

7 0

Answer

Use the distance formula to determine the distance between two points.

Exact Form:

√97

Tasya [4]3 years ago

6 0

Hope this will help u....

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Step-by-step explanation:

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adoni [48]

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Since we have given that

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$\dfrac{dy}{dx}=\dfrac{1}{[x(2x+3)^2]}\times [x'(2x+3)^2+(2x+3)^2'x]\\\\\dfrac{dy}{dx}=\dfrac{1}{[x(2x+3)^2]}\times [(2x+3)^2+2x(2x+3)]\\\\\dfrac{dy}{dx}=\dfrac{4x^2+9+12x+4x^2+6x}{x(2x+3)^2}\\\\\dfrac{dy}{dx}=\dfrac{8x^2+18x+9}{x(2x+3)^2}$

Hence, the required derivative is $\dfrac{8x^2+18x+9}{x(2x+3)^2}$

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3 years ago

Which expression is equivalent to 4r2/514.3V5r8, if x=0?

san4es73 [151]

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2 years ago

Can someone please help me and explain to me how to do this geometry problem please? thank you!! ❤

Dennis_Churaev [7]

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3 years ago

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