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Irina-Kira [14]
3 years ago
12

5/8 of 24 is equal to 15/7 of what number?

Mathematics
2 answers:
n200080 [17]3 years ago
8 0

Answer:

fddsdfsd

Step-by-step explanation:

sesfdf

Whitepunk [10]3 years ago
7 0

Answer:

7

Step-by-step explanation:

5/8 of 24 is 15

15/7 of 7 is 15

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Do the ratios 2-4 and 14-7 form a proportion
Nadya [2.5K]

Answer:

No

Step-by-step explanation:

because 2 is divisible by 14 but 4 is not divisible by 17

3 0
3 years ago
Read 2 more answers
When I am trying to find the whole of the percent and divide it what do I do with the remainder? Like do I put it together with
Sedaia [141]

Answer:

a. 9.48

b. 195.3

Step-by-step explanation:

convert the corresponding per cent into a decimal (you can move the decimal place to the left by 2 or divide by 100) then just multiply it with the "of" number

6 0
3 years ago
(a) The plane y + z = 13 intersects the cylinder x2 + y2 = 25 in an ellipse. Find parametric equations for the tangent line to t
klemol [59]

Answer:

Step-by-step explanation:

We have a curve (an ellipse) written as the system of equations

\begin{cases} y+z &= 13\\ x^2+y^2 &= 25\end{cases}.

And we want to calculate the tangent at the point (3,4,9).

The idea in this problem is to consider two variables as functions of the third. Usually we consider y and z as functions of x. Recall that a curve in the space can be written in parametric form in terms of only one variable. In this case we are considering the ‘‘natural’’ parametrization (x, y(x), z(x)).

Recall that the parametric equation of a line has the form

r(t)=\begin{cases} x(t) &= x_0 + v_1t \\ y(t) &= y_0 +v_2t\\ z(t) &= z_0 +v_3t \end{cases},

where (x_0,y_0,z_0) is a point on the line (in this particular case is (3,4,9)) and (v_1,v_2,v_3) is the direction vector of the line. In this case, the direction vector of the line is the tangent vector of the ellipse at the point (3,4,9).

Now, if we have the parametric equation of a curve (x, y(x), z(x)) its tangent line will have direction vector (1, y'(x), z'(x)). So, as we need to calculate the equation of the tangent line at the point (3,4,9) = (3, y(3), z(3)), we must obtain the tangent vector (1, y'(3), z'(3)). This part can be done taking implicit derivatives in the systems that defines the ellipse.

So, let us write the system as

\begin{cases} y(x)+z(x) &= 13\\ x^2+y^2(x) &= 25\end{cases}.

Then, taking implicit derivatives:

\begin{cases} y'(x)+z'(x) &= 0 \\ 2x+2y(x)y'(x) &= 0\end{cases}.

Now we substitute the values x=3 and y(3)=4, and we get the system of linear equations

\begin{cases} y'(3)+z'(3) &= 0 \\ 2\cdot 3+2\cdot 4y'(x) &= 0\end{cases},

where the unknowns are y'(3) and z'(3).

The system is

\begin{cases} y'(3)+z'(3) &= 0 \\ 6+8y'(x) &= 0\end{cases},

and its solutions are

y'(3) = -\frac{3}{4} and z'(3) = \frac{3}{4}.

Then, the direction vector of the tangent is

(1, -\frac{3}{4}, -\frac{3}{4}).

Finally, the tangent line has parametric equation

r(t)=\begin{cases} x(t) &= 3 + t \\ y(t) &= 4 -\frac{3}{4}t\\ z(t) &= 9 +\frac{3}{4}t \end{cases}

where t\in\mathbb{R}.

7 0
4 years ago
2x2-3x-2=x+4 select all the solutions
Papessa [141]
Solve for x over the real numbers:2 x^2 - 3 x - 2 = x + 4
Subtract x + 4 from both sides:2 x^2 - 4 x - 6 = 0
The left hand side factors into a product with three terms:2 (x - 3) (x + 1) = 0
Divide both sides by 2:(x - 3) (x + 1) = 0
Split into two equations:x - 3 = 0 or x + 1 = 0
Add 3 to both sides:x = 3 or x + 1 = 0
Subtract 1 from both sides:Answer:  x = 3 or x = -1
5 0
3 years ago
YeOOoOoOOoOoOooOoOOOoOOoooooOoOOOooO,
Arlecino [84]

Answer:

ok eereeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Step-by-step explanation:

4 0
3 years ago
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