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2 years ago

12

What do I do here is the math equation : Evan walked his dog 2.8 kilometers around the perimeter of a park.The is four time as m

uch as one lap. What was the distance of the 1st lap

1 answer:

Morgarella [4.7K]2 years ago

4 0

Answer:

2.8÷4

Step-by-step explanation:

if 2.8 is the 4th lap, you have to divide it by 4 to get the 1st lap.

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Answer:

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Answer:

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Step-by-step explanation:

Given the joint cumulative distribution of X and Y as

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$F_x(x)=F(x,100)\\\\\\=\frac{100x(x+100)}{2000000}\\\\\\\\=\frac{100x^2+10000x}{2000000}\\\\\\=>f_x(x)=\frac{x}{10000}+\frac{1}{200}$

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$E(X)=\int\limits^{100}_0 \frac{x^2}{10000}+\frac{x}{200} dx \\\\\\\\=|\frac{x^3}{30000}+\frac{x^2}{400}|\limits^{100}_0\\\\=58.33\\\\$

#We then calculate $E(X^2)$ :

$E(X^2)=\int\limits^{100}_0 \frac{x^3}{10000}+\frac{x^2}{200}\ dx\\\\=\frac{x^4}{40000}+\frac{x^3}{600}|\limits^{100}_0=4166.67\\\\Var(X)=E(X^2)-(E(X))^2=4166.67-58.33^2\\\\Var(X)=764.28$

Hence, the Var(X) is 764.28

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