Answer:
0.1
Explanation:
Using Henderson-Hasselbalch equation
pH = pKa + log ( base / acid )
pH= 9.0 , pKa = 10.0
9.0 = 10 + log ( base / acid )
9 - 10 = log ( base / acid )
10⁻¹ = ( base / acid )
( base / acid ) = 0.1
Answer:
The answer to your question is Ba(OH)₂ + 2HClO₄ ⇒ Ba(ClO₄)₂ + 2H₂O
Explanation:
Reactants
Barium hydroxide
Perchloric acid
Formula
Barium hydroxide = Ba(OH)₂
Perchloric acid = HClO₄
Equation (it is a double replacement)
Ba(OH)₂ + HClO₄ ⇒ Ba(ClO₄)₂ + H₂O
Reactants Elements Products
1 Ba 1
1 Cl 2
3 H 2
6 O 9
This reaction is unbalanced
2) Balance the chemical reaction
Ba(OH)₂ + 2HClO₄ ⇒ Ba(ClO₄)₂ + 2H₂O
Reactants Elements Products
1 Ba 1
2 Cl 2
4 H 4
10 O 10
Now the reaction is balanced
Products
Ba(ClO₄)₂ Barium perchloride
2H₂O water
A solution has an absorbance of 0.2 with a path length of 1 cm. Given the molar absorptivity coefficient is 59 cm⁻¹ M⁻¹, the molarity is 0.003 M.
<h3>What does Beer-Lambert law state?</h3>
The Beer-Lambert law states that for a given material sample, path length and concentration of the sample are directly proportional to the absorbance of the light.
A solution has an absorbance of 0.2 with a path length of 1 cm. Given the molar absorptivity coefficient is 59 cm⁻¹ M⁻¹, we can calculate the molarity of the solution using the following expression.
A = ε × b × c
c = A / ε × b
c = 0.2 / (59 cm⁻¹ M⁻¹) × 1 cm = 0.003 M
where,
- A is the absorbance.
- ε is the path length.
- b is the molar absorptivity coefficient.
- c is the molar concentration.
A solution has an absorbance of 0.2 with a path length of 1 cm. Given the molar absorptivity coefficient is 59 cm⁻¹ M⁻¹, the molarity is 0.003 M.
Learn more about the Beer-Lambert law here: brainly.com/question/12975133
The complete reaction of the problem, for better illustration, is
FeO(s) + CO(g) <--> Fe(s) + CO2(g)
The double-tailed arrow signifies that the reaction is in a dynamic chemical equilibrium. When the system is in equilibrium, the forward and the backward reaction rates have an equal ratio of Kp = 0.403 at 1000°C. The formula for Kp is
Kp = [partial pressure of products]/[partial pressure of reactants]
So, first, let's find the partial pressure of the compounds in the reaction.
FeO(s) + CO(g) <--> Fe(s) + CO2(g)
Initial x 1.58 0 0
Change -1.58 -1.58 +1.58 +1.58
------------------------------------------------------------------
Equilbrium x-1.58 0 1.58 1.58
Kp = [(1.58)(1.58)]/[(x-1.58)] = 0.403
x = 7.77 atm (this is the amount of excess FeO)
Therefore, the partial pressure of CO2 at equilibrium is 1.58 atm. There is no more CO because it has been consumed due to excess FeO.