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2 years ago

Which organisms use cellular respiration as a way to convert energy into usable form?

Chemistry

2 answers:

kvasek [131]2 years ago

7 0

All organisms.

(hope i helped u)

Verizon [17]2 years ago

6 0

I'm sorry I meant all organisms

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Why argon is octent ??

Ira Lisetskai [31]

Answer:

argon is octet because it has eight electrons in its valence shell

Explanation:

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3 years ago

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Can someone pls help :/

jeka57 [31]

Answer:

option C. Addition of protons to the atomic nucleus.

Explanation:

Elements are fundamentally made up of atoms. Atoms in turn has three sub particles.

These particles are; neutrons, electrons and protons.

The sub particles responsible for the mass of an atoms is basically the protons and neutrons. Going through the options;

The correct option is option C. Addition of protons to the atomic nucleus.

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3 years ago

Which of the following lists describes characteristics of a base? (3 points) Bitter taste, high pH, and caustic Bitter taste, lo

garik1379 [7]

Bitter taste, high pH, and caustic Bitter are the characteristics of base.

<h3>What are the characteristics of base?</h3>

Bases have bitter taste, soapy feel, turn red litmus paper blue. Bases are substances that contain metal oxides or hydroxides. Its pH is higher than 7 up to 14.

So we can conclude that bitter taste, high pH, and caustic Bitter are the characteristics of base.

Learn more about base here: brainly.com/question/3948796

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2 years ago

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What do you mean by chemical reaction ?

kherson [118]

A chemical reaction is a reaction that changes the molecular structure and is normally irreversible.

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3 years ago

15. What volume of CCI, (d = 1.6 g/cc) contain

anastassius [24]

Answer:

$\boxed{\text{(3) 9.6 L}}$

Explanation:

1. Moles of CCl₄

$n = 6.02 \times 10^{25} \text{ molecules} \times \dfrac{\text{1 mol}}{6.022 \times 10^{23}\text{ molecules}} = \text{100.0 mol}$

2. Molar mass of CCl₄

MM = 1 × 12.01 + 4 × 35.5 = 12.01 + 142 = 154.0 g/mol

3. Mass of CCl₄

$m =\text{100.0 mol} \times \dfrac{\text{154.0 g}}{\text{1 mol}} = \text{15 400 g}$

4. Volume of CCl₄

$V = \text{15 400 g} \times \dfrac{\text{1 cm}^{3}}{\text{1.6 g}} = \text{9600 cm}^{3}\\\\V = \text{9600 cm}^{3} \times \dfrac{\text{1 L}}{\text{1000 cm}^{3}} = \mathbf{{9.6 L}}\\\\\text{The volume of CCl$_{4}$ is } \boxed{\textbf{9.6 L}}$

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3 years ago