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Likurg_2 [28]
3 years ago
14

If 1.00 mol of argon is placed in a 0.500-l container at 22.0 ?c , what is the difference between the ideal pressure (as predict

ed by the ideal gas law and the real pressure (as predicted by the van der waals equation? for argon, a=1.345(l2?atm/mol2 and b=0.03219l/mol.
Chemistry
1 answer:
labwork [276]3 years ago
5 0
Calculate the pressure using the Van der Waals equation and the pressure using the ideal gas equation PV=nRT. Subtract the two pressures to get the difference. then:<span>Calculate how many moles of ammonia you have using the ideal gas equation PV=nRT. Multiply the number of moles by the molar mass of ammonia to get the mass in grams.</span>
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Which of the following is not a type of covalent bond?
puteri [66]

Answer:

Quadruple

Explanation:

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2 years ago
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If 448.85 mg of KOH is dissolved in 400 ml of water, what will be the pH of the solution?
emmasim [6.3K]
I have provided the steps and solution within the attachment. The pH of the solution would be 12.30, this indicates that the solution is basic, as a higher value of pH indicates presence of more hydroxide ions and less of hydrogen ions in the solution.

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4 years ago
Describe at least two ways that a researcher can minimize experimental errors in an investigation
snow_tiger [21]
Experimental errors occurs in the execution of experiment design. Example of experimental errors are  mistakes in data entry, systematic error, and random error caused by environmental conditions. Did you even heard about type I and type II error? Because that may be the 2 ways you are looking for.  
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5 0
3 years ago
Suppose that the mixture in problem 4 is at 15 OC, where the pure vapor pressures are 12.5 mmHg for water and 32.1 mmHg for etha
EleoNora [17]

Answer:

Explanation:

Since we are not given the mole fraction of ethanol and water; we will solve this theoretically.

Using Raoult's Law:

P_A = (P_o)_A*X_A

For water:

(P)w = P_o \times \text{mole fraction of water}

where P_o of water = 12.5 mmHg

Then, the vapor pressure of water:

(P)w = 12.5 \ mmHg \times \text{mole fraction of water}

For ethanol:

P_E = P_o \times \text {mole fraction of ethanol}

and the P_o of ethanol = 32.1 mmHg

Then, the vapor pressure of ethanol:

P_E = 32.1 \ mmHg \times \text {mole fraction of ethanol}

The total vapor pressure T_P = P_W + P_E

The total vapor pressure = (12.5 \ mmHg \times \text{mole fraction of water}) + (32.1 \ mmHg \times \text {mole fraction of ethanol})

3 0
3 years ago
Which of the following conditions must be met for a volume ratio to be created from a balanced chemical equation?
Gnesinka [82]

Answer: Option (b) is the correct answer.

Explanation:

According to ideal gas law, the product of pressure and volume is equal to the product of number of moles, gas constant and temperature.

Mathematically,           PV = nRT

So, when there are two gases with equal number of moles behaving ideally then the ideal gas equation will be as follows.

             \frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

and             \frac{V_{1}}{V_{2}} = \frac{P_{2}T_{1}}{P_{1}T_{2}}

Hence, when temperature and pressure of both the gases will be constant then \frac{V_{1}}{V_{2}} = 1.

Thus, we can conclude that constant temperature and pressure is the conditions that must be met for a volume ratio to be created from a balanced chemical equation.

4 0
3 years ago
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