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tresset_1 [31]
3 years ago
8

How

Mathematics
1 answer:
andrey2020 [161]3 years ago
6 0

Answer: 7800

Step-by-step explanation:

As English alphabet has 26 letters.

So , Choices for First character in the code = 26

The choices for digits = 10  (From 0 to 9)

So , choices for second character = 10  (Middle two characters must be numbers)

choices for third character = 10            (Middle two characters must be numbers)

Choices for last character = 3   (the  last character must be a 1, 3, or 7)

By Fundamental principle of counting , the total number of four character codes can be generated =

(Choices for First character)x (choices for digits) x(choices for digits) x(Choices for last character)

= (26) (10)(10)(3) =7800

Hence, the total number of character codes can be generated= 7800

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Babies born after 40 weeks gestation have a mean length of 52.2 centimeters (about 20.6 inches). Babies born one month early hav
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Answer:

a) Z = -2.88

b) Z = -0.96

c) 40 weeks gestation babies

Step-by-step explanation:

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Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

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Here, we use \mu = 52.2, \sigma = 2.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{45 - 52.2}{2.5}

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Here, we use \mu = 47.4, \sigma = 2.5. So

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For each group, the probability is 1 subtracted by the pvalue of Z.

Z = -2.88 has a lower pvalue than Z = -0.96, so for Z = -2.88 the probability 1 - pvalue of Z will be greater. This means that for 40 weeks gestation babies a birth length of 45 cm is more common.

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