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4 years ago

Use the sequence to answer the following

Mathematics

1 answer:

ser-zykov [4K]4 years ago

7 0

The common difference is 3.5
The nth term rule for this equation would be 3.5n-1

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Given: measure of angle KJ = 124°, measure of IC =38° Find: m∠CQJ, m∠LIJ.

VLD [36.1K]

Answer:

Part 1) $m$

Part 2) $m$

Step-by-step explanation:

Part 1) Find the measure of angle CQJ

we know that

The measure of the interior angle is the semi-sum of the arcs comprising it and its opposite.

$m$

$arc\ IK+arc\ CJ=360\°-(arc\ IC+arc\ KJ)$

substitute the values

$arc\ IK+arc\ CJ=360\°-(38\°+124\°)=198\°$

$m$

Part 2) Find the measure of angle LIJ

step 1

Find the measure of angle IJL

we know that

The inscribed angle is half that of the arc it comprises.

$m$

substitute the values

$m$

step 2

Find the measure of angle ILJ

we know that

The measurement of the external angle is the semi-difference of the arcs it encompasses.

$m$

substitute the values

$m$

step 3

Find the measure of angle LIJ

Remember that the sum of the interior angles of a triangle must be equal to 180 degrees

In the triangle LIJ

$m$

substitute the values

$m$

3 0

4 years ago

1/3(z+4)-6=2/3(5-z)

chubhunter [2.5K]

Answer:

hope my answer is helpful to you

plz mark me as brainlist and also follow me

7 0

3 years ago

Engineers must consider the breadths of male heads when designing helmets. The company researchers have determined that the popu

tia_tia [17]

Answer:

The minimum head breadth that will fit the clientele is 4.4 inches.

The maximum head breadth that will fit the clientele is 7.8 inches.

Step-by-step explanation:

Let X = head breadths of men that is considered for the helmets.

The random variable X is normally distributed with mean, μ = 6.1 and standard deviation, σ = 1.

To compute the probability of a normal distribution we first need to convert the raw scores to z-scores using the formula:

$z=\frac{x-\mu}{\sigma}$

It is provided that the helmets will be designed to fit all men except those with head breadths that are in the smallest 4.3% or largest 4.3%.

Compute the minimum head breadth that will fit the clientele as follows:

P (X < x) = 0.043

⇒ P (Z < z) = 0.043

The value of z for this probability is:

z = -1.717

*Use a z-table.

Compute the value of x as follows:

$z=\frac{x-\mu}{\sigma}\\-1.717=\frac{x-6.1}{1}\\x=6.1-(1.717\times 1)\\x=4.383\\x\approx4.4$

Thus, the minimum head breadth that will fit the clientele is 4.4 inches.

Compute the maximum head breadth that will fit the clientele as follows:

P (X > x) = 0.043

⇒ P (Z > z) = 0.043

⇒ P (Z < z) = 1 - 0.043

⇒ P (Z < z) = 0.957

The value of z for this probability is:

z = 1.717

*Use a z-table.

Compute the value of x as follows:

$z=\frac{x-\mu}{\sigma}\\1.717=\frac{x-6.1}{1}\\x=6.1+(1.717\times 1)\\x=7.817\\x\approx7.8$

Thus, the maximum head breadth that will fit the clientele is 7.8 inches.

5 0

3 years ago

6 millones restado 300¿

Brut [27]

Step-by-step explanation:

6,000,000-300=5,999,700

4 0

3 years ago

Read 2 more answers

Whats the answer to 48.001 to hundredths

cestrela7 [59]

48.00 is the answer your looking for

6 0

3 years ago