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Gre4nikov [31]
3 years ago
7

Can someone help “is 9 a factor of 23p - 47

Mathematics
2 answers:
quester [9]3 years ago
6 0

Answer:

No.

Step-by-step explanation:

9 Does not go into 47 or 23

faltersainse [42]3 years ago
5 0
9 is not a factor of 23 or 47
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Use green's theorem to compute the area inside the ellipse x252+y2172=1. use the fact that the area can be written as ∬ddxdy=12∫
Pavel [41]

The area of the ellipse E is given by

\displaystyle\iint_E\mathrm dA=\iint_E\mathrm dx\,\mathrm dy

To use Green's theorem, which says

\displaystyle\int_{\partial E}L\,\mathrm dx+M\,\mathrm dy=\iint_E\left(\frac{\partial M}{\partial x}-\frac{\partial L}{\partial y}\right)\,\mathrm dx\,\mathrm dy

(\partial E denotes the boundary of E), we want to find M(x,y) and L(x,y) such that

\dfrac{\partial M}{\partial x}-\dfrac{\partial L}{\partial y}=1

and then we would simply compute the line integral. As the hint suggests, we can pick

\begin{cases}M(x,y)=\dfrac x2\\\\L(x,y)=-\dfrac y2\end{cases}\implies\begin{cases}\dfrac{\partial M}{\partial x}=\dfrac12\\\\\dfrac{\partial L}{\partial y}=-\dfrac12\end{cases}\implies\dfrac{\partial M}{\partial x}-\dfrac{\partial L}{\partial y}=1

The line integral is then

\displaystyle\frac12\int_{\partial E}-y\,\mathrm dx+x\,\mathrm dy

We parameterize the boundary by

\begin{cases}x(t)=5\cos t\\y(t)=17\sin t\end{cases}

with 0\le t\le2\pi. Then the integral is

\displaystyle\frac12\int_0^{2\pi}(-17\sin t(-5\sin t)+5\cos t(17\cos t))\,\mathrm dt

=\displaystyle\frac{85}2\int_0^{2\pi}\sin^2t+\cos^2t\,\mathrm dt=\frac{85}2\int_0^{2\pi}\mathrm dt=85\pi

###

Notice that x^{2/3}+y^{2/3}=4^{2/3} kind of resembles the equation for a circle with radius 4, x^2+y^2=4^2. We can change coordinates to what you might call "pseudo-polar":

\begin{cases}x(t)=4\cos^3t\\y(t)=4\sin^3t\end{cases}

which gives

x(t)^{2/3}+y(t)^{2/3}=(4\cos^3t)^{2/3}+(4\sin^3t)^{2/3}=4^{2/3}(\cos^2t+\sin^2t)=4^{2/3}

as needed. Then with 0\le t\le2\pi, we compute the area via Green's theorem using the same setup as before:

\displaystyle\iint_E\mathrm dx\,\mathrm dy=\frac12\int_0^{2\pi}(-4\sin^3t(12\cos^2t(-\sin t))+4\cos^3t(12\sin^2t\cos t))\,\mathrm dt

=\displaystyle24\int_0^{2\pi}(\sin^4t\cos^2t+\cos^4t\sin^2t)\,\mathrm dt

=\displaystyle24\int_0^{2\pi}\sin^2t\cos^2t\,\mathrm dt

=\displaystyle6\int_0^{2\pi}(1-\cos2t)(1+\cos2t)\,\mathrm dt

=\displaystyle6\int_0^{2\pi}(1-\cos^22t)\,\mathrm dt

=\displaystyle3\int_0^{2\pi}(1-\cos4t)\,\mathrm dt=6\pi

3 0
3 years ago
Translation is a congruency transformation. True or false
frutty [35]

Answer:

True

Step-by-step explanation:

In a translation, the figures face the same direction and are congruent.

5 0
2 years ago
Read 2 more answers
The workers in a senate office said that they received about 700 phone calls from
prohojiy [21]

Answer:

672

Step-by-step explanation:

anything lower then 5 or in this case 50 would round down so 649 rounds to 600 anything higher would round up 672 to 709 763 to 800 and 751 to 800

7 0
3 years ago
Find the missing term (x^12)^5 x (x^-2)^9 x what =(x^40)^5
Annette [7]

Answer:

x^{158}

Step-by-step explanation:

We are given,

(x^{12} )^{5} \times (x^{-2} )^{9} \times y = (x^{40} )^{5}.

It is required to find the value of y.

Now, on simplifying above equation, we get,

x^{60} \times x^{-18} \times y = x^{200}

i.e. x^{42} \times y = x^{200}

i.e. y = x^{200} \times x^{-42}

i.e. y = x^{158}

Hence, the missing term is x^{158}.

3 0
3 years ago
Read 2 more answers
Victor is thinking of a number. If he multiplies his number by nine and then subtracts 7, he
dalvyx [7]

Answer:12

Step-by-step explanation:

12x9=108

108-7=101

Your welcome

8 0
3 years ago
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