9514 1404 393
Answer:
- 2% growth per year
- 25,000 to start
- 12 years
- 31,706 currently
Step-by-step explanation:
The base of the exponent is (1 +0.02). The value 0.02 = 2% is the growth rate. It is positive, signifying a 2% rate of growth per year. (Negative values would mean decay.)
The number 25000 that multiplies the exponential term is the value of the expression when the exponent is zero. It represents the starting population.
The exponent is said to be in years, so the time is 12 years.
The current population is the value of the expression:
25,000(1.02^12) ≈ 31,706 . . . . current population
Answer:
Step-by-step explanation:
6 = 2(1+2)
Use distributive property (Multiply 2 and 1. Then multiply 2 and 2)
6 = 2+4
Now add
6=6
This means the statement is true
Answer:

Step-by-step explanation:
Height of the Rectangle
Width of the Rectangle
Area of the Rectangle = Height X Width

The area of the rectangle is 
Assuming you meant 3 dozen for a bag of flour the answers 4
If you meant 3 cookies for a bag of flour the answers 10
Answer:

Step-by-step explanation:
So we have the equation:

And we want to solve for g.
First, isolate g. To do so, subtract vt from both sides:

Multiply both sides by 2:

Now, divide both sides by t^2:

Expand:

Simplify the second term:

And we're done!