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2 years ago

A growth factor is a value that is greater than 1?

Mathematics

1 answer:

amm18122 years ago

6 0

Answer:

No, it is a value that is greater than 0

Step-by-step explanation:

A growth factor is indeed a value greater than 1 except it can be a decimal below 1 to. Therefore, a growth value is any POSITIVE number.

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What is the expression in factored form x2 + 14x + 48

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Factor using the AC method...

The answer is:

(x+6) (x+8)

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3 years ago

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2 years ago

Please help me again one last time for this lol.

Darina [25.2K]

Answer:

3/8 = 9/24 ; 1/3 = 8/24 ; 3/8 > 1/3

Step-by-step explanation:

You have to multiply 8 and 3 to obtein the same number as denominatoe (24).

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3 years ago

Test the series for convergence or divergence (using ratio test)

Triss [41]

Answer:

$\lim_{n \to \infty} U_n =0$

Given series is convergence by using Leibnitz's rule

Step-by-step explanation:

Step(i):-

Given series is an alternating series

∑ $(-1)^{n} \frac{n^{2} }{n^{3}+3 }$

Let $U_{n} = (-1)^{n} \frac{n^{2} }{n^{3}+3 }$

By using Leibnitz's rule

$U_{n} - U_{n-1} = \frac{n^{2} }{n^{3} +3} - \frac{(n-1)^{2} }{(n-1)^{3}+3 }$

$U_{n} - U_{n-1} = \frac{n^{2}(n-1)^{3} +3)-(n-1)^{2} (n^{3} +3) }{(n^{3} +3)(n-1)^{3} +3)}$

Uₙ-Uₙ₋₁ <0

Step(ii):-

$\lim_{n \to \infty} U_n = \lim_{n \to \infty}\frac{n^{2} }{n^{3}+3 }$

$= \lim_{n \to \infty}\frac{n^{2} }{n^{3}(1+\frac{3}{n^{3} } ) }$

= $= \lim_{n \to \infty}\frac{1 }{n(1+\frac{3}{n^{3} } ) }$

$=\frac{1}{infinite }$

$\lim_{n \to \infty} U_n =0$

∴ Given series is converges

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2 years ago

The line at the bullet roller coaster is moving about 4 feet for every 15 minutes. At this rate, how many hours would it take fo

Brums [2.3K]

Answer:

Step-by-step explanation:

4/15 which is our fraction distance/time

our other fraction is 24/x (x is our variable to find our time)

Now we are doing the buultterfly method

set it up

now multiply 4*x= 4x

15*24=360

now divide 4x ÷ 4 to get our variable alone

do the same to the other side

4 ÷ 360= 90

so x= 90 which is our missing number

8 0

3 years ago