Answer:
The distance covered is 40 m and the displacement is 31,6m.
Explanation:
The distance covered is the sum of the two distances (10+30). The displacement is equal to the distance of the hipotenusa of the triangle that the two distances (10 m to north and 30m to east) create. Using the Pythagoras theorem the displacent is equal to the Square root of (30^2 +10^2) .
It has a flexible vertibrae which allows it to move faster and fit into places . Plus it also allows it to get its prey easier
It’s the crest, the crest is the top part of the wave and the trough is the bottom so they correspond
Short Answer
3: C
4: D
Problem Three
Remark
Somewhere we ought to be told that this is the Doppler Effect. I have never done a problem using this formula, so I think I'm doing it correctly, but no guarantees. My guess is that the frequency increases as it comes towards you and decreases as it moves away from you. I think that is correct.
Formula
<em><u>Givens</u></em>
- f' = observed frequency
- f = actual frequency
- v = velocity of sound or light waves.
- vo = velocity of observer (in both cases 0)
- vs = velocity of source.
f' = (v + vo) * f / (v - vs)
Solution
- v = 3*10^8 m/s
- f' = 1.1 f
- f = f
- vo = 0 We are standing still while all this is going on.
- vs = ???
f'/f = 1.1
1.1 = (3*10^8 + 0 ) / (3*10^8 - vs)
3.3*10^8 - 1.1*vs = 3*10^8
3.3*10^8 - 3*10^8= 1.1 vs
0.3 * 10^8 = 1.1 vs
2.73 * 10^7 = vs
The closest answer is 3.00 * 10^7 which is C
Problem Four
Here what is happening is that you are looking for the frequency resulting from a wave moving towards you at 1/2 the speed of sound. You are not moving.
<em><u>Givens</u></em>
- v = v
- vs = 1/2 v
- f ' = ?
- f = 1000 hz
- vo =0
f' = v/(v - 1/2v) * 1000
f' = v/ (1/2 v) * 1000
f' = 2 * 1000
f' = 2000 which is D
False. A sound wave is an example of a mechanical wave, not an EM wave.
Hope this helps! :)
