Answer:
The tension in the rod as the ball moves through the bottom circle is 9.8 N
Explanation:
When the ball is released from rest, the centripetal force equals the weight of the ball. So mv²/r = mg where m = mass of ball = 0.5 kg, v = speed of ball, r = radius of vertical circle = length of rod = 0.5 m and g = acceleration due to gravity = 9.8 m/s²
v = √gr = √9.8 m/s² × 0.5 m = √4.9 = 2.21 m/s
Now at the bottom of the circle T - mg = mv²/r where T = tension in the rod
T = m(g + v²/r)
= m(g + (√gr)²/r)
= m(g+ gr/r)
= m(g + g)
= 2mg
= 2 × 0.5 kg × 9.8 m/s²
= 9.8 N
So, the tension in the rod as the ball moves through the bottom circle is 9.8 N
Answer:
a).
b).
Explanation:
a).
Using the law of thermodynamic and using to isovolumetric
ΔU=Qh
So to determine the internal energy knowing the work it do
b).
Efficiency is the work done in relation of the work apply in this case to produce heat so:
Solve to Qc
A.simple machine hpoe u get it
Answer:
Magnitude of electric field is 1.06 x V/m along negative X-direction
Explanation:
Given: initial velocity of proton = u = 3.5 x m/s
final velocity of proton = v = 0 m/s
initial point = 0.2 m and final point is = 0.8 m
According to conservation of energy:
change in in kinetic energy = change in potential energy of proton
⇒
where q and m is the charge and mass of proton E is the electric field , and is the initial and final position of proton
on substituting the respected values we get,
1.023 x = 9.6 x x E
⇒ E = 1.06 x V/m
external force is opposite to the motion as velocity of proton decreases with distance.
Therefore, magnitude of electric field is 1.06 x V/m along negative X-direction
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