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antiseptic1488 [7]
3 years ago
7

Why is an increase in speed a curved line on a position vs. time graph but a straight diagonal line on a speed vs. time graph?

Physics
1 answer:
guapka [62]3 years ago
7 0
What do you need help with
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Unlike acceleration and velocity, speed does not need to specify
frosja888 [35]

Unlike acceleration and velocity, speed does not need to specify the direction of motion. Speed is a scalar quality.

4 0
3 years ago
Which of the following is true about all of the outer planets?A.Much of the material in these planets is solid.B.The surface of
Lisa [10]
The awnsers is D all the planet's in the solar system rotate the same direction or else they would bump into each other
4 0
3 years ago
Did I do these questions correctly?
SOVA2 [1]
Yes, they seem right to me.
4 0
4 years ago
A person slaps her leg with her hand, which results in her hand coming to rest in a time interval of 2.65 ms from an initial spe
dezoksy [38]

Answer:

the magnitude of the average contact force exerted on the leg is  3466.98 N

Explanation:

Given the data in the question;

Initial velocity of hand v₀ = 5.25 m/s

final velocity of hand v = 0 m/s

time interval t = 2.65 ms = 0.00265 s

mass of hand m = 1.75 kg

We calculate force on the hand F_{hand

using equation for impulse in momentum

F_{hand × t = m( v - v₀ )

we substitute

F_{hand × 0.00265  = 1.75( 0 - 5.25 )

F_{hand × 0.00265  = 1.75( - 5.25 )

F_{hand × 0.00265  = -9.1875

F_{hand = -9.1875 / 0.00265  

F_{hand = -3466.98 N

Next we determine force on the leg F_{leg

Using Newton's third law of motion

for every action, there is an equal opposite reaction;

so, F_{leg = - F_{hand

we substitute

F_{leg = - ( -3466.98 N )

F_{leg = 3466.98 N

Therefore, the magnitude of the average contact force exerted on the leg is  3466.98 N

5 0
3 years ago
10 poin<br> What is the momentum of a 25kg cart traveling left with a velocity of 10<br> m/s?
Mashutka [201]
250 kg*m/s
Momentum is found by multiplying mass by velocity
25*10=250
7 0
3 years ago
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