Weird way to write it but alright! (Sideways)
19pq^-2 x 5pq^6 = ?
These problems are pretty much single operations between each of the variables / constants.
So it's like this:
(19*5)(p*p)(q^-2*q^6) = ?
19*5 is 95.
For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2.
p*p is p^2
For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this:
-2 + 6 = 4
(The two is negative, because the power is negative 2)
So, q^4.
Our final answer is all of the combined.... like a so:
95p^2q^4
Answer:
-3.2, -3.4, -3.6, -3.8, -3.9
Step-by-step explanation:
<em>Hey there!</em>
<em />
Well rational numbers can be a decimal as long as it can be turned into a fraction, meaning 3.5 is a rational number.
So rational numbers between -3 and -4 are,
-3.2, -3.4, -3.6, -3.8, -3.9
<em>Hope this helps :)</em>
Answer:
5y^5
Step-by-step explanation:
there is no real solution. really i just simplified. if you wanted a real answer y would have to be giving. if not then this is all the question is asking. for you to simplify
Answer:
B
Step-by-step explanation:
the area of triangle A is k times the area of triangle b
Answer:
Step-by-step explanation:
<u>We can see points:</u>
- (1, 1), (2, 2), (3, 3) etc.
<u>It shows the proportional relationship:</u>
- y = x, where the slope is 1
