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2 answers:
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The square of a prime number is not prime.
a) let x ∈ R, If x ∈ {prime numbers}, then ∉{prime numbers}
there says that if x is a real and x is in the set of the prime numbers, then the square of x isn't in the set of prime numbers.
b) Prove or disprove the statement.
ok, if x is a prime number, then x only can be divided by himself. Now is easy to see that = x*x can be divided by himself and x, then x*x is not a prime number, because can be divided by another number different than himself
Question is not complete and so I have attached the complete question.
Answer:
C: f(x) = -½x + 4
Step-by-step explanation:
Using slope formula between 2 points, we know that;
slope; m = (y2 - y1)/(x2 - x1)
Let's consider 2 points from the table;
(0, 4) and (-4, 6)
Thus;
m = (6 - 4)/(-4 - 0)
m = 2/-4
m = -½
Now using slope intercept form equation which is y - y1 = m(x - x1), we can find the equation of the function by picking on point say (0, 4).
Thus;
y - 4 = -½(x - 0)
y - 4 = -½x
y = -½x + 4
Thus;
f(x) = -½x + 4
