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Zigmanuir [339]
3 years ago
8

Treatment of an alpha,beta-unsaturated ketone with basic aqueous hydrogen peroxide yields an epoxy ketone. the reaction is speci

fic to unsaturated ketones; isolated alkene double bonds do not react. on a sheet of paper, write a mechanism for the alkene to epoxide reaction. then, in the window below, draw the first intermediate in your mechanism.

Chemistry
1 answer:
Misha Larkins [42]3 years ago
5 0
The reaction mechanism for an alpha,beta-unsaturated ketone to react with basic peroxide to form an epoxide is shown below with a general ketone. The basic hydroxide is used to deprotonate the peroxide molecule to create a strong HOO- nucleophile. The peroxide then attacks the beta-carbon of the alkene and this pushes the electrons up to the oxygen of the carbonyl. This is the first intermediate that is formed during this reaction.

After the intermediate is formed, the lone pair from the oxygen pushes back down to form the carbonyl once more and this breaks a carbon-carbon bond which attacks the oxygen of the peroxy group, ultimately substituting an -OH group and forming the final epoxide ketone product.

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Imagine two solutions with the same concentration and the same boiling point, but one has benzene as the solvent and the other h
Degger [83]

Answer:

Molality of both benzene and carbon tetrachloride is 1.32 m .

boiling point is 83.4396 °C

Explanation:

When a non-volaile solute is added to a solvent, its boiling point increases. The relationship increase in temperature and molality of the solute is given as follows:

ΔT = m × Kb

Boiling point of pure benzene is 80.1 °C.

Molal elevation boiling constant of benzene (k_b) is 2.53 °C/m

Increase in boiling point of benzene = m × 2.53

Therefore, Boiling point of benzene solution = 80.1 + 2.53m

Boiling point of pure carbon tetrachloride is 76.8 °C

Molal elevation boiling constant of carbon tetrachloride (k_b) is 5.03 °C/m

Increase in boiling point of benzene = m × 5.03

Therefore, Boiling point of carbon tetrachloride solution = 76.8 + 5.03m

It is given that boiling point of both the solutions are same therefore,

76.8 + 5.03m = 80.1 + 2.53m

5.03m - 2.53m = 80.1 - 76.8

2.5m = 3.3

m = 1.32  

Molality of both benzene and carbon tetrachloride is 1.32 m

Boiling point of the solutions = 80.1 + 2.53 × 1.32

                                            = 83.4396 °C

6 0
3 years ago
When n = 4, l = 2, and ml = -1, to what orbital type does this refer?
Leya [2.2K]

will tell you the subshell type, so you are dealing with a d orbital.  

ml will tell you the orientation of the orbital, there is no distinction between the orbitals so -1 doesnt specifically mean anything.

5 0
3 years ago
Assuming all volume measurements are made
Katarina [22]

Answer:

2H2  +  O2 ------------->  2H2O

I would guess therefore 2 x 2.50 L or 5.00 L

Explanation:

4 0
3 years ago
Which of the following causes the formation of ionic bonds
pantera1 [17]

Answer: b. One atom transferring electrons to another atom

Explanation: An ionic bond is formed when an element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element and the element which accepts the electrons is known as electronegative element. This bond is formed between a metal and an non-metal.

Covalent bonds are formed by sharing of electrons between non metals

For example, In calcium iodide the one electron from calcium metal gets transferred to iodine atom and thus form an ionic bond to give CaI_2

Electronic configuration of calcium:

[Ca]=1s^22s^22p^63s^23p^64s^2

Calcium atom will lose two electron to gain noble gas configuration and form calcium cation with +2 charge.

[Ca^{2+}]=1s^22s^22p^63s^23p^6

Electronic configuration of iodine:

[I]=1s^22s^22p^63s^23p^64s^23d^{10}4p^5

Iodine atom will gain one electron to gain noble gas configuration and form iodide ion with -1 charge.

[I^-]=1s^22s^22p^63s^23p^64s^23d^{10}4p^6

7 0
3 years ago
In the density of a liquid activity, the graph had an intercept. If you were to make a similar graph using metal blocks, would t
Alex17521 [72]

Answer:

NO

Explanation:

<u>It would be difficult to plot a line of best fit on the scattered graph of the activities of metal blocks as the activities would almost be the same horizontally on the graph</u> and an attempt to draw/determine an intercept will be almost impossible.  The line of best fit is usually drawn to determine the relatedness/correlation of the variables.

Drawing intercept for the activities of the liquid is easier because a line of best fit can be easily placed between the clustered liquid activities on the scattered plot.

8 0
3 years ago
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