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morpeh [17]
3 years ago
15

Force exerted on a lever is applied on the lever's

Chemistry
1 answer:
Cerrena [4.2K]3 years ago
7 0
A force called the effort force is applied at one point on the lever in order to move an object, known as the resistance force, located at some other point on the lever
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A gas sample is held at constant pressure. The gas occupies 2.97 L of volume when the temperature is 21.6°C. Determine the tempe
STALIN [3.7K]

Answer:

339.2K

Explanation:

Using Charles law equation;

V1/T1 = V2/T2

Where;

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question,

V1 = 2.97 L

V2 = 3.42 L

T1 = 21.6°C = 21.6 + 273 = 294.6K

T2 = ?

Using V1/T1 = V2/T2

2.97/294.6 = 3.42/T2

Cross multiply

2.97 × T2 = 294.6 × 3.42

2.97T2 = 1007.532

T2 = 1007.532 ÷ 2.97

T2 = 339.236

The final temperature is 339.2K

5 0
3 years ago
How is popcorn good for protecting a egg?
bezimeni [28]

Answer:Possibilities include balloons, popcorn, packing peanuts, wads of paper or cereal puffs. Encase the egg in any of these inside a paper or plastic bag, a sock or a stocking. If you have any bubble wrap around the house, wrapping the egg in several layers of bubble wrap should also provide a good cushion

Explanation:

7 0
3 years ago
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Please Help! Thank You
ra1l [238]

Answer:

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Explanation:

im confuzzled

6 0
3 years ago
A certain protein was found to contain 0.292% manganese by mass. Determine the minimum molecular mass of the protein.
Lisa [10]
55u \ \ \ \ \ \ \Rightarrow \ \ \ \ \ 0,292\%\\
x \ \ \ \ \ \ \ \ \ \Rightarrow \ \ \ \ \ 100\%\\\\
x = \frac{55u*100\%}{0,292\%}\approx18835,62u
4 0
3 years ago
2. What is the mass of 5.3 moles of CaCl2?
Tanya [424]

Answer:

590 g CaCl₂

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

5.3 mol CaCl₂

<u>Step 2: Identify Conversions</u>

Molar Mass of Ca - 40.08 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of CaCl₂ - 40.08 + 2(35.45) = 110.98 g/mol

<u>Step 3: Convert</u>

<u />5.3 \ mol \ CaCl_2(\frac{110.98 \ g \ CaCl_2}{1 \ mol \ CaCl_2} ) = 588.194 g CaCl₂

<u>Step 4: Check</u>

<em>We are given 2 sig figs. Follow sig fig rules and round.</em>

588.194 g CaCl₂ ≈ 590 g CaCl₂

5 0
3 years ago
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