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timurjin [86]
3 years ago
14

GR 11 CHEM M3

Chemistry
1 answer:
galina1969 [7]3 years ago
6 0

<em>A:  When burning Sulfur, Sulfur Dioxide is released. Having more Oxygen available provides more reactive potential for the burning Sulfur, making it burn much more fiercely. In water, the Sulfur Dioxide forms Sulfurous acid. Added: 12 years ago.</em>

<em />

<em>Explanation:</em>

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Could someone please help me? You can ignore number 3:)
il63 [147K]

Answer:

Question 2: Because the elements could be unstable, forming elemental compounds.

Question 1: Water is made up of Hydrogen and oxygen, which is namely called H2^o What makes it a pure substance is the little mass and molecules it's made up of.

6 0
2 years ago
If 16.00 g of O₂ reacts with 80.00 g NO, how many grams of NO₂ are produced? (enter only the value, round to whole number)
Norma-Jean [14]

Answer:

46 g

Explanation:

The balanced equation of the reaction between O and NO is

2 NO  +  O₂  ⇔  2 NO₂

Now, you need to find the limiting reagent.  Find the moles of each reactant and divide the moles by the coefficient in the equation.

NO:  (80 g)/(30.006 g/mol) = 2.666 mol

        (2.666 mol)/2 = 1.333

O₂:  (16 g)/(31.998 g/mol) = 0.500 mol

     (0.500 mol)/1 = 0.500 mol

Since O₂ is smaller, this is the limiting reagent.

The amount of NO₂ produced will depend on the limiting reagent.  You need to look at the equation to determine the ratio.  For every mole of O₂ reacted, 2 moles of NO₂ are produced.

To find grams of NO₂ produced, multiply moles of O₂ by the ratio of NO₂ to O₂.  Then, convert moles of NO₂ to find grams.

0.500 mol O₂ × (2 mol NO₂/1 mol O₂) = 1.000 mol NO₂

1.000 mol × 46.005 g/mol = 46.005 g

You will produce 46 g of NO₂.

6 0
3 years ago
If you had 100 ml of juice, how many milliliter would de fruit juice?
Julli [10]
Since the measurement is not changing, the answer is 100 mL. Hope this helps.
8 0
3 years ago
I) Briefly discuss the strengths and weaknesses of the four spectroscopy techniques listed below. Include in your answer the spe
klemol [59]

delete please .....................................

4 0
3 years ago
Consider the following reaction:
Katyanochek1 [597]

Answer:

The three statements are true

Explanation:

For the reaction:

I₂O₅(s) + 5CO(g) → I₂(s) + 5CO₂(g)

State oxidation of iodine in I₂O₅ is:

5 O²⁻ = 10⁻

As you have 2 I and the molecule has no charge, <em>oxidation state of I is +5</em>.

The carbon in CO has an oxidation state of +2 and in CO₂ is +4. That means <em>the carbon is oxidized</em>

<em />

An oxidizing agent is a substance that produce the oxidation of the agent that reacts with this one. CO is oxidized because of I₂O₅ is producing its oxidation being <em>the oxidizing agent</em>

<em></em>

Thus,<em> the three statements are true</em>.

3 0
3 years ago
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