Answer:
1837.89 Lt
Explanation:
The chemical reaction for this situation is:
NaHCO₃ + HCl → NaCL + H₂O + CO₂ ₍g₎
Where the mola mass we need are:
M NaHCO₃ = 84 g/mol
M CO₂ = 44 g/mol
As we have 6.00 Kg of sodium bicarbonate, then:
6 Kg NaHCO₃ = 71.43 moles of NaHCO₃
Due the stoichiometry of this chemaicl reaction:
1 mol NaHCO₃ = 1 mol CO₂
71.43 moles NaHCO₃ = 71.43 moles CO₂
And considering that CO₂ is an ideal gas, we can use the following formula:
PV=nRT
V = (nRT)/P
n = 71.43 mol
R = 0.083 Ltxatm(molxK)
T = 37°C = 310 K
P = 1 atm
So: V = (71.43x0.083x310)/1
V CO₂ = 1837.89 Lt
<span>Both samples have a mass of 1 g.
Suppose the first sample has a generic mass, X, of 0.34 then it follows that the mass of Y = 1 - 0.34 = 0.66g. So we have a mass ratio of 0.34 : 0.66 where our ratio is of the form X : Y. If we divide by the smallest mass we end up with 1 : 1.94. But Since 1.94 ~ 97/50 then we multiply through by 50, when we do, we end up with a chemical form of the form X50Y97. On the other hand if the sample has a mass of 0.44 of Y then it also follows that the mass of X = 1 - 0.44 = 0.56. So we have a mass ratio of 0.56 : 0.44. If we divide by the smallest mass we end up with 1.27 : 1. Since 1.27 ~ 127/100 then if we multiply through by 100, we end up with a chemical form X127Y100</span>
Answer:
For the drawing, please refer to the attachment below
Explanation:
In this E1 reaction, chlorocyclopentane in the aquaeous solution releases Cl as anion leaving carbon C in the ring positively charged. The intermediate which appears is now highly reactive and sensible for oxygen electron pair in water molecule . This intermediate acts like a Lewis acid; it gives away hydrogen to available electron pair on the oxygen creating hydronim ion as the result of protonation of the water molecule. The final product is cyclopentene.
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Explanation: