Answer:
97
Step-by-step explanation:
bc
Answer:
Area of the new rectangle = 148.8 cm square
Step-by-step explanation:
Let x be the dimensions of the rectangle then the
Perimeter of the Original rectangle= 2(L+B)
= 2 ( 3x+2x) = 2(5x)= 10xcm
If the length is increased by eight the new length would be 3x+ 8
and width would be 2x+x= 3x after 50 % increase
Perimeter of the new rectangle= 2(L+B)
= 2 ( 3x+8 +3x)
= 2 (6x+8)
= 12x + 16
Ratio of the new perimeter to the original perimeter is
New perimeter : Original perimeter
8 : 5
12x+ 16 : 10x cm
80x= 60x + 16
20x= 16
x= 16/20= 4/5
Putting the value of length and breadth in place of x
Area of the new rectangle = L*B = 3 * (4/5) +8 *3(4/5)=
= 12+ 40/5 * 12/5
= 62/5* 12/5
= 744/5
= 148.8 cm square
Let's begin ! ^_^
You have got informations in your problem that you just have to translate in a "mathematic language".
Company A :
"$40 membership fee and $2 per video stream."
Thanks to that, you can guess :
c = 40 + 2s
Now let's do the same thing to the company B.
Company B :
"charges a one-time $20 membership fee and $4 per video stream."
Therefore, c = 20 + 4s.
I think you have guessed !! =D And yes the system of equation that you have to solve and you're looking for is :
{c=40+2s ( Option B)
c=20+4s.
Second step : For how many video streams will the cost be the same for both companies?
We just have to solve the system :) And there is only one variable, the letter "s".
We know that we have to find equal costs as it is said in the question " the cost be the same for both companies", so :
=> 40 + 2s = 20 +4s
=> 4s - 2s = 40 - 20
=> 2s = 20
=> s = 20/2
=> s = 10
Verification :
Company A :
=> 40 + 2s = 40 + 2*10 = 40 + 20 =60.
Company B :
=> 20 + 4s = 20 + 4*10 = 20 + 40 = 60
As you have seen, the costs are the same for both companies.
We can say that as a conclusion for 10 video streams, the cost will be the same for both companies.
In short, the answer would be : 10.
Let me give you an advice : Usually the word "per" means a multiplication is the mathematic language.
Hope this helps !
Photon
