2 years ago

Please please help.........

Mathematics

1 answer:

Brums [2.3K]2 years ago

7 0

Answer:

I think the working is actually unnecessary because of (x-c)=0 and if x is 5 (5-c)=0 c would be 5

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3 years ago

Rearrange the formula a2 + b2 = c2 for a. A) a = (c2 − b2)2 B) a = (c2 + b2)2 C) a = c2 − b2 D) a = c2 + b2

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3 years ago

Read 2 more answers

A rectangular tank that is 5324 ft cubed with a square base and open top is to be constructed of sheet steel of a given thicknes

marishachu [46]

Answer:

Side of 22 and height of 11

Step-by-step explanation:

Let s be the side of the square base and h be the height of the tank. Since the tank volume is restricted to 5324 ft cubed we have the following equation:

$V = s^2h = 5324$

$h = 5324 / s^2$

As the thickness is already defined, we can minimize the weight by minimizing the surface area of the tank

Base area with open top $s^2$

Side area 4sh

Total surface area $A = s^2 + 4sh$

We can substitute $h = 5324 / s^2$

$A = s^2 + 4s\frac{5324}{s^2}$

$A = s^2 + 21296/s$

To find the minimum of this function, we can take the first derivative, and set it to 0

$A' = 2s - 21296/s^2 = 0$

$2s = 21296/s^2$

$s^3 = 10648$

$s = \sqrt[3]{10648} = 22$

$h = 5324 / s^2 = 5324 / 22^2 = 11$

4 0

2 years ago

Can someone help me with math?

Paladinen [302]

Answer:

The second step because she distributed within the parentheses without adding the negative sign to 13

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2 years ago