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kipiarov [429]
2 years ago
12

Please please help.........

Mathematics
1 answer:
Brums [2.3K]2 years ago
7 0

Answer:

I think the working is actually unnecessary because of (x-c)=0 and if x is 5 (5-c)=0 c would be 5

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The binomial x-2 is a factor of the polynomial below. f(x)=x3+x2+nx+10 What is the value of n?
Nutka1998 [239]
<h3>Answer: n = -11</h3>

=========================================================

Explanation:

Since x-2 is a factor of f(x), this means f(2) = 0.

More generally, if x-k is a factor of p(x), then p(k) = 0. This is a special case of the remainder theorem.

So if we plugged x = 2 into f(x), we'd get

f(x) = x^3+x^2+nx+10

f(2) = 2^3+2^2+n(2)+10

f(2) = 8+4+2n+10

f(2) = 2n+22

Set this equal to 0 and solve for n

2n+22 = 0

2n = -22

n = -22/2

n = -11 is the answer

Therefore, x-2 is a factor of f(x) = x^3+x^2-11x+10

Plug x = 2 into that updated f(x) function to find....

f(x) = x^3+x^2-11x+10

f(2) = 2^3+2^2-11(2)+10

f(2) = 8+4-22+10

f(2) = 0

Which confirms our answer.

3 0
3 years ago
From a standard deck of 52 cards, what is the probability of picking a King at random from the deck?
MaRussiya [10]

Answer:

1/13

Step-by-step explanation:

there are 4 kinds and 52 cards so its 4/52 which simplifies to 1/13

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Answer:

678

Step-by-step explanation:

First you have to do 666-66 which is 600. Then you add 777 which is 1377. Then you add 90 which is 1467. Last you subtract 789.

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