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Sedaia [141]
3 years ago
7

First, rewrite 9/10 and 11/12 so that they have a common denominator

Mathematics
1 answer:
Licemer1 [7]3 years ago
6 0

Step-by-step explanation:

Find common denominators:

\frac{9}{10}  \times  \frac{12}{12}  =  \frac{108}{120}

\frac{11}{12}  \times  \frac{10}{10}  =  \frac{110}{120}

Now compare:

\frac{108}{120} <  \frac{110}{120}

so \:  \frac{9}{10}  <   \frac{11}{12}

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Find the distance between the points.<br><br> (-4,2), (-4,-5)<br><br> The distance is _<br> .
MaRussiya [10]

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Which coordinate pair identifies a point in the third quadrant of the coordinate plane? A) (0, 5) B) (7,0) C) (0,0) D) (-6, -2)
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6 0
3 years ago
Noah gathered data at his school among 7th and 8th graders to see if there was an association between grade level and handedness
mash [69]

Answer: 4) 157

Step-by-step explanation:

We know that there is no association between the grade level and the andedness, then we should find that the ratio between left handeds and right handed is the same for both grades.

In 7-th grade we have:

Left handed : 11

Right handed: 72

The ratio is 11/72 = 0.14

Then, the ratio for the 8-th graders must be about the same:

Left handed: 24

Right handed: X

Ratio: 24/X

Let's start with the bigger option, X = 157.

24/157 = 0.15

Ok, we now see that with the bigger option we obtained almost the same ratio (if we use the smaller values for X, we will get a ratio bigger than 0.15, so 0.15 is the better aproximation that we can find to the 0.14 of the 7-th graders)

Then the correct option is 4) 157

4 0
3 years ago
Quadrilateral PQRS is a square whos side length is 10. Let X and Y be points outside the square so that XQ = YS = 6 and XP = YR
erik [133]

Answer:

392

Step-by-step explanation:

Triangles XQP and YRS are right triangles because triples 6, 8, 10 are Pythagorean triples.

Extend lines XQ, YR, YS and XP and mark their intersection as A and B.

Quadrilateral XAYB is a square because all right triangles PXQ, QAR, RYS and SBP are congruent (by ASA postulate) and therefore

  • all angles of the quadrilateral XAYB are right angles
  • all sides of XAYB are congruent and equal to 6 + 8 = 14 units.

Segment XY is the diagonal of the square XAYB, by Pythagorean theorem,

XY^2=XA^2+AY^2\\ \\XY^2=14^2+14^2\\ \\XY^2=196+196\\ \\XY^2=392  

3 0
3 years ago
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