Step-by-step explanation:
2×-3. don't worry about the - for now. 2 times 3 is 6. so 6/5 improper fraction. plus 1. 1 6/5. yeah
Answer:
Area of bigger circle = 36.32cm²
Step-by-step explanation:
Kindly find attached rough sketch for your reference
This problem bothers on the mensuration of flat shapes, a circle
Kindly find attached
Given data
Area of small circle =9cm³
Say we assume the all unit is in cm
From the diagram we can see that the diameter of the small circle is the radius of the bigger circle
So let us solve for the diameter of the small circle
9= πr²
r²=9/3.142
r²= 2.86
r=√2.86
r= 1.7cm
But diameter of small circle
d= 2r
d= 1.7*2= 3.4cm
Hence the radius of the bigger circle is 3.4cm
Area of bigger circle =πr²
=3.142*3.4²
=3.142*11.56
Area of bigger circle = 36.32cm²
Answer:
square miles
inches
Step-by-step explanation:
Analyzing the options:
- cubic feet: this is a measure of volume because 1 cubic feet represents the volume of a cube with measures 1 feet on each side. In general, when a measure of length, such as the foot is cubed, it represents a volume.
- square miles: This is not a measure of volume but of area, a square mile represents the area of a square with sides that measure one mile. So this option is not a measure of volume
- inches: is a measure of length, not volume
: Cubic centimeters are a measure of volume, because a cubic meter is the volume of a cube with sides of a centimeter.
Thus the answer is that:
square miles and inches
are not appropiate for volume
The answer is B because C and D are not true. Angle-Angle theorem does not prove congruency. Hypotenuse-Leg does because having a hypotenuse means that the triangle is a right angle triangle, which means that 2 sides and an angle are congruent in the triangles. By Side-Side-Angle Theorem, the triangles are congruent.
III. If E={1, 2, 3, 4, 5, 6, 7, 8, 9, 10) A=(2, 3, 5, 7), B=(1, 3, 5, 7, 9) List the following sets: a) (AUB) b) (AnB) c) AnB' d
tresset_1 [31]
Step-by-step explanation:
A u B = { 1,2,3,5,7,9}
AnB = { 3,5,7}
B' = {2,4,6,8,10}
so AnB' = {2}
(AnB) = {1,3,4,5,6,7,8,9,10}
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