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Tasya [4]
3 years ago
11

Number sets of the square root of 15

Mathematics
1 answer:
Len [333]3 years ago
5 0

Answer:

the square root is 15=5

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The weights of a certain brand of candies are normally distributed with a mean weight of 0.8544 g and a standard deviation of 0.
aleksandr82 [10.1K]

Answer:

The probability is 0.508 = 50.8%.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean weight of 0.8544 g and a standard deviation of 0.0525 g.

This means that \mu = 0.8544, \sigma = 0.0525

If 1 candy is randomly​ selected, find the probability that it weighs more than 0.8535 g.

This is 1 subtracted by the pvalue of Z when X = 0.8535. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.8535 - 0.8544}{0.0525}

Z = -0.02

Z = -0.02 has a pvalue of 0.492

1 - 0.492 = 0.508

The probability is 0.508 = 50.8%.

8 0
3 years ago
Parallel lines in space are coplanar.
kakasveta [241]
Coplanar lines are line witch lie on the same lie on the same plane. two parallel lines or two intersecting lines always lie in a plane. Thus, two line are coplanar, if and only if they are either parallel or intersecting. lines in three dimensional space are coplanar, only if they are not skewed lines.
3 0
4 years ago
Using the following image, if you EG = 59, what are x, EF, and FG.
Harman [31]

Answer:

x=6\,\,units\,,\,EF=34 \,\,units\,,\,FG=25\,\,units

Step-by-step explanation:

Given: EG =59 \,\,units

To find: x,EF,FG

Solution:

From the image, EG=EF+FG

Put EF=8x-14\,,\,FG=4x+1\,,\,EG=59

8x-14+4x+1=59\\12x-13=59\\12x=59+13\\\\12x=72\\x=\frac{72}{12}=6

EF=8x-14=8(6)-14=48-14=34\\FG=4x+1=4(6)+1=24+1=25

Therefore,

x=6\,\,units\,,\,EF=34 \,\,units\,,\,FG=25\,\,units

8 0
3 years ago
Find the area of the figure
Eduardwww [97]

Answer:

132cm²

Step-by-step explanation:

You can find the area of the entire shape by calculating the area of seperate smaller shapes.

You can split them up into 2 rectangles, one with a base of 7cm and height of 4cm, and another one with a base of 7cm and height of 8cm. You also have 2 triangles, with a base of 19cm - 7cm / 2 = 6cm since it is the entire bottom line subtracted by the top; they will have a height of 8cm each.

To calculate the rectangles areas, simply do length x width, which are:

4cm x 7cm = 28cm²

8cm x 7cm = 56cm²

Next, since the triangles are similar in measurements, instead of doing the normal calculation to find the area of a triangle, you can do base times height again, which is:

6cm x 8cm = 48cm²

Add all the answers together to get the final area, which is 132cm².

8 0
3 years ago
Which ordered pair is a solution to the system of inequalities?
Butoxors [25]

For this case, what we must do is find a point that meets both inequalities.

  • <em>y> -2 </em>
  • <em>x + y <4 </em>

We have then:

For (0,4):

First inequation:

4> -2 (correct)

Second inequality:

0 + 4 <4 (incorrect)

For (1,4):

First inequation:

4> -2 (correct)

Second inequality:

1 + 4 <4 (incorrect)

For (-3,5):

First inequation:

5> -2 (correct)

Second inequality:

-3 + 5 <4 (correct)

Point (-3,5) is system solution

For (-2,-3):

First inequation:

-3> -2 (incorrect)

Answer:

Point (-3.5) is system solution

5 0
4 years ago
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