Answer:
70.34 litres
Explanation:
Using ideal gas law equation;
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
T = temperature (K)
According to the information given in the question;
n = 3 moles
V = ?
P = 105.2 KPa = 105.2/101 = 1.04atm
T = 24.0°C = 24 + 273 = 297K
Using PV = nRT
1.04 × V = 3 × 0.0821 × 297
1.04V = 73.15
V = 73.15 ÷ 1.04
V = 70.34 litres.
<span>Answer:
CuX = Cu2+ + X2-
Ksp = [Cu2+] * [X2-]
for each mole of CuX that dissolves we get x mol of each of the anions and cations
Ksp = x^2 = 1.27 x 10 ^-36
x= 1.13 x 10 ^-18 moles of CuX per liter of pure water
if the solution has [Cu2+]= 0.27 M
Ksp becomes x ( x + 0.27)
as we can see above x is extremely small so can be ignored inside the brackets
0.27 x = 1.27 x 10^-36
x = 1.27 x 10^-36 / 0.27 = 4.70 x 10 ^-36 moles per liter
In 0.19M X2- we have
Ksp = 0.19x = 1.27 x 10^-36
x = 1.27 x 10^-36 / 0.19 = 6.68 x 10 ^-36 moles per liter</span>
Answer:
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Explanation:
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Answer:
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" 2 Li + Br2<span> ----> 2 LiBr " .
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Explanation:
Molar mass
The mass present in one mole of a specific species .
The molar mass of a compound , can easily be calculated as the sum of the all the individual atom multiplied by the number of total atoms .
(a) P₄
Molar mass of of the atoms are -
Phosphorous , P = 31 g/mol
Molecular mass of P₄ = ( 4 * 31 ) = 124 g/mol .
(b) H₂O
Molar mass of of the atoms are -
Hydrogen , H = 1 g/mol
oxygen , O = 16 g/mol.
Molecular mass of H₂O = ( 2 * 1 ) + ( 1 * 16 ) = 18 g/mol
(c) Ca(NO₃)₂
Molar mass of of the atoms are -
calcium , Ca = 40 g/mol
nitrogen, N = 14 g/mol
oxygen , O = 16 g/mol.
Molecular mass of Ca(NO₃)₂ = ( 1 * 40 ) + ( 2 * 14 ) + ( 6 * 16 ) = 164 g/mol.
(d)CH₃CO₂H (acetic acid)
Molar mass of of the atoms are -
Carbon , C = 12 g/mol.
oxygen , O = 16 g/mol.
Hydrogen , H = 1 g/mol
Molecular mass of CH₃CO₂H =( 2 * 12 ) + (2 * 16 ) + (4 * 1 ) = 60 g/mol.
(e) C₁₂H₂₂O₁₁ (sucrose, cane sugar).
Molar mass of of the atoms are -
Carbon , C = 12 g/mol.
oxygen , O = 16 g/mol.
Hydrogen , H = 1 g/mol
Molecular mass of C₁₂H₂₂O₁₁ = (12 * 12 ) + ( 22 * 1 ) + ( 11 * 16 ) = 342 g/mol.