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xxMikexx [17]
3 years ago
8

Calculate the Molecular or Formula massof each of the following:

Chemistry
1 answer:
DiKsa [7]3 years ago
4 0

Explanation:

Molar mass  

The mass present in one mole of a specific species .

The molar mass of a compound , can easily be calculated as the sum of the all the individual atom multiplied by the number of total atoms .

(a) P₄

Molar mass of of the atoms are -

Phosphorous , P = 31 g/mol

Molecular mass of  P₄ = ( 4 * 31 ) = 124 g/mol .

(b) H₂O

Molar mass of of the atoms are -

Hydrogen , H = 1 g/mol

oxygen , O = 16 g/mol.

Molecular mass of H₂O = ( 2 * 1 ) + ( 1 * 16 ) = 18 g/mol

(c) Ca(NO₃)₂

Molar mass of of the atoms are -

calcium , Ca = 40 g/mol

nitrogen, N = 14 g/mol

oxygen , O = 16 g/mol.

Molecular mass of  Ca(NO₃)₂ = ( 1 * 40 ) + ( 2 * 14 ) + ( 6 * 16 ) = 164 g/mol.

(d)CH₃CO₂H (acetic acid)

Molar mass of of the atoms are -

Carbon , C = 12 g/mol.

oxygen , O = 16 g/mol.  

Hydrogen , H = 1 g/mol

Molecular mass of CH₃CO₂H =( 2 * 12 ) + (2 * 16 ) + (4 * 1 ) = 60 g/mol.

(e) C₁₂H₂₂O₁₁ (sucrose, cane sugar).

Molar mass of of the atoms are -

Carbon , C = 12 g/mol.

oxygen , O = 16 g/mol.  

Hydrogen , H = 1 g/mol

Molecular mass of C₁₂H₂₂O₁₁ = (12 * 12 ) + ( 22 * 1 ) + ( 11 * 16 ) = 342 g/mol.

 

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Taking into account the reaction stoichiometry and the definition of STP, 5.4 L of carbon dioxide is produced.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

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The following rule of three can be applied: if by reaction stoichiometry 1 mole of C₃H₈ form 3 moles of CO₂, 0.080 moles of C₃H₈ form how many moles of CO₂?

amount of moles of CO_{2} =\frac{0.080 moles of C_{3} H_{8}x3 moles of CO_{2} }{1 mole of C_{3} H_{8} }

<u><em>amount of moles of CO₂= 0.24 moles</em></u>

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The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

<h3>Volume of CO₂ produced</h3>

You can apply the following rule of three: If by definition of STP 1 mole of CO₂ occupies 22.4 L, 0.24 moles of CO₂ how much volume does it occupy?

volume of CO_{2} =\frac{0.24 molesx22.4 L}{1 mole}

<u><em>volume of CO₂= 5.376 L ≅ 5.4 L</em></u>

Finally, 5.4 L of carbon dioxide is produced.

Learn more about

the reaction stoichiometry:

<u>brainly.com/question/24741074</u>

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STP conditions:

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<u>brainly.com/question/8846039</u>

<u>brainly.com/question/1186356</u>

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