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hoa [83]
3 years ago
6

Complete the area model representing the polynomial x2 - 11x + 28. What is the factored form of the polynomial? Use the model to

Mathematics
1 answer:
Alex73 [517]3 years ago
6 0
(X-7)(X-4) Should be the answer at least the factoring for it
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Solve for x.<br> I was sure the answer was 2?<br> Please show me the breakdown. THX
Murljashka [212]

Answer:

x = 8 and y = 10

Step-by-step explanation:

Since the figures are congruent:

Angle PQR = EFG

6y + x = 68

Segment QR = FG

2x - 4 = 12

Solving that:

2x - 4 = 12

2x = 16

x = 8

Replacing x in 6y + x =68

6y + 8 = 68

6y = 60

y = 10

7 0
4 years ago
You wish to accumulate $14,580 in 6 years. Payments are made at the end of every six-month period into an account earning 7.2% c
BlackZzzverrR [31]
Equation required for this question:

an • 1.072^n = 14,580

Where a = payment every half year and n = number of half years

There are 12 half years in 6 years.

Therefore n = 12, substitute this.

12a • 1.072^12 = 14,580

12a = 14,580 / 1.072^12

12a = 6,330~

a = 527.5 ~
7 0
4 years ago
If F^-1(x) if f(x) = (x-2)^2 for &gt;2
-BARSIC- [3]
I don’t see the choices
6 0
3 years ago
What is the discontinuity and zero of the function
lukranit [14]
The discontinuity are the point wherein the function is not defined. 
The zeros are the points wherein f(x)=0.
Computing the discontinuity points:
Set x-1=0 then the discontinuity point is at x=1.
Comptine the zeroes:
Set 3x^2+x-4=0
Compute the discriminant: 1^2-4(3)(-4)=49=7^2.
Then with quadratic formula we get the solutions:
(-1-7)/6=-8/6\\(-1+7)/6=1
The two zeros are \dfrac{-8}{6},1
7 0
3 years ago
Help me plz I’m struggling with this
elena-s [515]

Answer:

AC = 8√3       AC = 7.65          

A = 43.17°       AB = 16.8

B = 46.83°      B = 27°

Step-by-step explanation:

FIRST TRIANGLE

by using pythagorus theorem:

Hypo² = Base² + height²

19² = 13² + AC²

AC² = 19² - 13²

AC² = 192

AC = √192

AC = 8√3

sinФ =base/hypo

sin A = 13/19

A = sin^-1 (13/19)

A = 43.17°

43.17°+ B + 90° =180 (sum of angles of triangle)

B = 180° - 133.17°

  = 46.83°

<h3>SECOND TRIANGLE</h3>

TanФ = base/height

Tan 63° = 15 / AC

1.96 = 15/AC

AC = 15/1.96

AC = 7.65

AB² = AC² + BC²

AB² = 7.65² + 15²

AB² = 283.5

AB = √283.5

AB = 16.8

tan B = AC /BC

tanФ = 7.65/15

tanФ = 0.51

Ф = tan^-1(0.51)

B = 27°

3 0
4 years ago
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