Answer:
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![step\:1](https://tex.z-dn.net/?f=step%5C%3A1)
![\frac{1}{ \sqrt{3} - \sqrt{2} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B%20%5Csqrt%7B3%7D%20-%20%20%5Csqrt%7B2%7D%20%20%7D%20)
write the equation
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![step\:2](https://tex.z-dn.net/?f=step%5C%3A2)
![\frac{1 \times ( \sqrt{3} + \sqrt{2}) }{ (\sqrt{3} - \sqrt{2} ) \times (\sqrt{3} + \sqrt{2}) }](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%20%5Ctimes%20%28%20%5Csqrt%7B3%7D%20%2B%20%20%5Csqrt%7B2%7D%29%20%20%7D%7B%20%28%5Csqrt%7B3%7D%20-%20%20%5Csqrt%7B2%7D%20%29%20%5Ctimes%20%20%28%5Csqrt%7B3%7D%20%20%2B%20%20%5Csqrt%7B2%7D%29%20%20%7D%20)
multiply both numerator and denominator by √3+√2
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![step\:3](https://tex.z-dn.net/?f=step%5C%3A3)
![\frac{ \sqrt{3} + \sqrt{2} }{ ( 3 ) - ( 2 ) }](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%5Csqrt%7B3%7D%20%2B%20%20%5Csqrt%7B2%7D%20%20%7D%7B%20%28%203%20%29%20-%20%28%202%20%29%20%7D%20)
after multiplying numerator with √3+√2 we get→√3+√2
after multiplying denominator we get 3-2
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![step\:4](https://tex.z-dn.net/?f=step%5C%3A4)
![\frac{ \sqrt{3} + \sqrt{2} }{1}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%5Csqrt%7B3%7D%20%20%2B%20%20%5Csqrt%7B2%7D%20%7D%7B1%7D%20)
after subtracting 3 with 2 we get →1
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hence denominater is rationalized✓
hope it helped you:)