Answer:
Answer is E hope this helps :)
Step-by-step explanation:
Answer:
<u><em>the comuter does 1 calculation in 1.5*
nanosec</em></u>
Step-by-step explanation:
<u><em>First step: we need to write all terms in nanosec, as we know:</em></u>
<u><em>1[nanosec]= 
[sec]</em></u>
<u><em>The computer does 6.7*
[
]</em></u>
<u><em>if we multiplicate for 
, from the units convertion.</em></u>
<u><em>6.7* [ * </em></u>
<u><em>6.7* 
[
]</em></u>
<u><em>Now doing a simple three rule we have this:</em></u>
<u><em>6.7 * calculation in ⇒ 1 nanosec</em></u>
<u><em>1 calculation in ⇒ 
</em></u>
<u><em>So, we found: the comuter does 1 calculation in 1.5* nanosec</em></u>
A:B = 2:3
A=126
B=?
126/2=63
63x3=189
A=126
B=189
A:B = 126:189
Answer:
1/169
Step-by-step explanation:
There are 4 aces in a deck of 52.
The probability that the first card is an ace is 4/52.
Since the card is replaced, the probability that the second card is an ace is also 4/52.
The total probability is (4/52) (4/52) = 1/169.
Answer:
Point N(3,0) is equidistant from A and B.
Step-by-step explanation:
In order to check whether the point is equidistant from A and B, it is required to measure the distance of A and B from each point. The formula for distance is:
d= √((x_2-x_(1))^2+(y_2-y_(1))^2 )
For J
AJ= √((-4-0)^2+(-5+4)^2 )
=√((-4)^2+(-1)^2 )
= √(16+1)
= √17 units
BJ=√((-4+2)^2+(-5-0)^2 )
=√((-2)^2+(-5)^2 )
= √(4+25)
= √29 units
Point J is not equidistant from A and B.
For K
AK= √((-3-0)^2+(0+4)^2 )
=√((-3)^2+(4)^2 )
= √(9+16)
= √25 units
=5
BK=√((-3+2)^2+(0-0)^2 )
=√((-1)^2+(0)^2 )
= √(1+0)
= √1
=1 unit
Point K is not equidistant from A and B.
For M
AM= √((0-0)^2+(0+4)^2 )
=√((0)^2+(4)^2 )
= √(0+16)
= √16
=4 units
BM=√((0+2)^2+(0-0)^2 )
=√((2)^2+(0)^2 )
= √(4+0)
= √4
=2 units
Point M is not equidistant from A and B.
For N
AN= √((3-0)^2+(0+4)^2 )
=√((3)^2+(4)^2 )
= √(9+16)
= √25
=5 units
BN=√((3+2)^2+(0-0)^2 )
=√((5)^2+(0)^2 )
= √(25+0)
= √25
=5 units
As point N's distance is equal from A and B, Point N is equidistant from A and B.
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