Answer:
A) ERROR
B) ∠C = 26°
Step-by-step explanation:
Houston, We have a problem!!! too much information
If we had a legit triangle, the law of sines would hold
19/sin138 = 8/sin20
28.395 = 23.390
as this is NOT an equality, the triangle does not exist as described.
IF it did, we'd get different results depending on which set we used
∠F = 180 - 138 - 20 = 22°
Law of sines
19/sin138 = DE/sin22 ⇒ DE = 19sin22/sin138 = <u>10.63697...</u>
or
8/sin20 = DE/sin22 ⇒ DE = 8sin22/sin20 = <u>8.762211...</u>
If we attempt to use Law of cosines
DE² = 19² + 8² - 2(19)(8)cos22 = <u>11.9639...</u>
so really none is correct because we attempt to use trig calculations to a non-triangle.
12) AC² = 15² + 19² - 2(15)(19)cos120
AC = 29.51270...
29.51270 / sin120 = 15/sinC
C = arcsin(15sin120/29.51270) = 26.1142... <u>26°</u>
f is given as -3
-3 is greater than -4, so use the second equation 3x-5.
replace x with -3 and calculate:
3(-3) - 5 = -9 - 5 = -14
The answer is -14.
3/4. triangle FHE and triangle KMN; triangle GEH and triangle LNM
3y^-4 × (2y^-4) = 6y^-8
= 6/1/y^8
= 6/y^8
.................................................
1) When x^1 multiply with x^2, 1 will add to 2 and become 3
= x^3
2) y^-1 = 1/y
3^-2 = 1/3^2 = 1/9
5^-2 = 1/5^2 = 1/25
the value of the dimes is 10(21 - 5)
hope this helps
