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3 years ago

3х (2x + 16) Solve for x

Mathematics

1 answer:

pentagon [3]3 years ago

4 0

Answer:

Step-by-step explanation:

Step 1:

3x = 2x + 16 Equation

Step 2:

3x - 2x = 16 Subtract 2x on both sides

Answer:

x = 16

Hope This Helps :)

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Solve each system by elimination by multiplying both equations. eliminate y first. show all work.

Alex17521 [72]

First $\mathrm{Multiply\:}10x-3y=18\mathrm{\:by\:}3:\quad 30x-9y=54$
Then $\mathrm{Multiply\:}6x-10y=-22\mathrm{\:by\:}5:\quad 30x-50y=-110$
To get $\begin{bmatrix}30x-9y=54\\ 30x-50y=-110\end{bmatrix}$
So...
$30x-50y=-110 \ \textgreater \ \begin{bmatrix}30x-9y=54\\ -41y=-164\end{bmatrix}$
$-41y=-164 \ \textgreater \ \mathrm{Divide\:both\:sides\:by\:}-41 \ \textgreater \ \frac{-41y}{-41}=\frac{-164}{-41}$
To get y = 4.
$\mathrm{For\:}30x-9y=54\mathrm{\:plug\:in\:} \:y=4 \ \textgreater \ 30x-9\cdot \:4=54$
$\mathrm{Multiply\:the\:numbers:}\:9\cdot \:4=36 \ \textgreater \ 30x-36=54 \ \textgreater \$
Next $\mathrm{Add\:}36\mathrm{\:to\:both\:sides} \ \textgreater \ 30x-36+36=54+36 \ \textgreater \ \mathrm{Simplify} \ \textgreater \ 30x=90$
Finally $\mathrm{Divide\:both\:sides\:by\:}30 \ \textgreater \ \frac{30x}{30}=\frac{90}{30} \ \textgreater \ x = 3$
Therefore our solutions are y = 4, x = 3

8 0

3 years ago

How is this equation completed? I cannot find any examples in the book.

djverab [1.8K]

Answer: Option D

$t_{max} =19\ s$

Step-by-step explanation:

Note that the projectile height as a function of time is given by the quadratic equation

$h = -12t ^ 2 + 456t$

To find the maximum height of the projectile we must find the maximum value of the quadratic function.

By definition the maximum value of a quadratic equation of the form

$at ^ 2 + bt + c$ is located on the vertex of the parabola:

$t_{max}= -\frac{b}{2a}$

Where $a$

In this case the equation is: $h = -12t ^ 2 + 456t$

Then

$a=-12\\b=456\\c=0$

So:

$t_{max} = -\frac{456}{2*(-12)}$

$t_{max} =19\ s$

7 0

3 years ago

I need help with geometry

andrew-mc [135]

What do you need help with?

8 0

4 years ago

Read 2 more answers

I want 5kg of rice.

nikdorinn [45]

The best possible choice for addition will be given by

a) Cost of 5 boxes of 1 kg rice = £7

b) Cheapest way to buy 5 kg rice is by buying 2 kg + 2 kg+ 1 kg and the

cost is £6.7

What is addition?

Bringing two or more numbers together to find a new total is called addition.

Here,

a) Cost of 1 kg rice = £1.4

Cost of 5 boxes of 1 kg rice = £1.4 * 5

= £7

b) Possible ways of buying 5kg rice

1) 1 kg + 1 kg + 1 kg + 1 kg + 1 kg

2) 1 kg + 1 kg + 1 kg + 2 kg

3) 1 kg + 1 kg + 1.5 kg + 1.5 kg

4) 2 kg + 2 kg + 1 kg

Now

cost of rice in 1) = £(1.40 + 1.40 + 1.40 + 1.40 + 1.40) = £7

cost of rice in 2) = £(1.40 + 1.40 + 1.40 + 2.65) = £6.85

cost of rice in 3) = £(1.40 + 1.40 + 2.05 + 2.05) = £6.9

cost of rice in 4) = £(2.65 + 2.65 + 1.40) = £6.7

Cheapest way to buy 5 kg rice is by buying 2 kg + 2 kg+ 1 kg and the cost is £6.7

To learn more about addition, refer to the link:

brainly.com/question/5982761

#SPJ9

Complete Question

A shop sells three different sized boxes of rice. Nice Rice 1kg £1.4, 1.5 kg

£2.05, 2kg 2.65

a) I want of rice. I could buy five boxes of size . How much would that cost? b) I could buy of rice in different ways. How much would it cost to buy of rice in the cheapest way possible?

4 0

2 years ago

Help please thank you

suter [353]

The answer is 5/8.hope this helps

3 0

3 years ago

Read 2 more answers