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3 years ago

Given four functions, which one will have the highest y-intercept?

1 answer:

6 0

Here are the four functions :
1) Blake is tracking his savings account with an interest rate of 5% and a original deposit of $6.
Equation : y = 0.05x + 6
y-intercept = (0,6)

2) x g(x)
1 6
2 8
3 12
y-intercept = (0,5)

3) The function h of x equals 4 to the x power, plus 3
equation : y = 4^x + 3
y-intercept = (0,4)

4) j(x) = 10(2)x
y-intercept = (0,1)

Best choice : f(x) has the highest y-intercept.

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Simplify 3 (2x+4y-2z)+7 (x+y-4z)

Dima020 [189]

6x+12y-6z+7x7y-28z= 13x+19y-34z

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3 years ago

There is a bag with only milk and dark chocolates. The probability of randomly choosing a dark chocolate is 5 12 . There are 40

Maksim231197 [3]

Answer:

There must be 96 milk chocolates.

Step-by-step explanation:

If you take the original ratio, 5:12, and replace the 5 with 40, you'd discover that 40 divided by 5 is 8. So what do you do? You multiply the 12 by 8 to get 96 so now the ratio is 40:96.

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2 years ago

2x² - 5x+1 has roots alpha and beta. Find alpha⁴+beta⁴ without solving the equation.

shepuryov [24]

Answer:

Step-by-step explanation:

$\alpha+\beta=\dfrac{5}{2} \\\\\alpha*\beta=\dfrac{1}{2} \\\\\alpha^2+\beta^2=\dfrac{21}{4} \ (see\ previous\ post)\\\\(\alpha+\beta)^4=\dfrac{625}{16} \\\\=\alpha^4+\beta^4+4*\alpha^3*\beta+6*\alpha^2*\beta^2+4*\alpha*\beta^3\\\\=\alpha^4+\beta^4+4*(\alpha*\beta)(\alpha^2+\beta^2)+6*\alpha^2*\beta^2\\\\\alpha^4+\beta^4=(\alpha+\beta)^4-4*(\alpha*\beta)(\alpha^2+\beta^2)-6*\alpha^2*\beta^2\\\\= \dfrac{625}{16} -4*\dfrac{1}{2} *\dfrac{21}{4} -6*(\dfrac{1}{2})^2 \\\\$

$= \dfrac{625}{16}- \dfrac{168}{16}-\dfrac{24}{16}\\\\\\= \dfrac{433}{16}$

7 0

3 years ago

What 3 dividenb by 186 long divison

Jlenok [28]

Answer: 62

Step-by-step explanation:

See picture for more information

8 0

3 years ago

Help me with this question for brainliest please

Pepsi [2]

Answer:

Step-by-step explanation:

We want to find the surface area, which will essentially just be the areas of all the figures given in the net.

We have two congruent triangles and 3 different rectangles.

Triangles:

The area of a triangle is denoted by: A = (1/2) * b * h, where b is the base and h is the height. The base here is 3 and the height is 4, so:

A = (1/2) * b * h

A = (1/2) * 3 * 4 = 6

Since there are two triangles, multiply 6 by 2: 6 * 2 = 12 cm squared

Rectangles:

The area of a rectangle is denoted by: A = b * h, where b is the base and h is the height.

The base of the leftmost rectangle is 4 and the height is 7, so:

A = b * h

A = 4 * 7 = 28

The base of the middle rectangle is 3 and the height is 7, so:

A = b * h

A = 3 * 7 = 21

The base of the rightmost rectangle is 5 and the height is 7, so:

A = b * h

A = 5 * 7 = 35

Add these together:

12 + 28 + 21 + 35 = 96 cm squared

The answer is thus A.

8 0

3 years ago