Given :
Initial speed of car A is 15 m/s and initial speed of car B is zero.
Final speed of car A is zero and final speed of car B is 10 m/s.
To Find :
What fraction of the initial kinetic energy is lost in the collision.
Solution :
Initial kinetic energy is :
Final kinetic energy is :
Now, fraction of initial kinetic energy loss is :
Therefore, fraction of initial kinetic energy loss in the collision is 1.25 .
To solve this question, we need to use the component method and split our displacements into their x and y vectors. We will assign north and east as the positive directions.
The first movement of 25m west is already split. x = -25m, y = 0m.
The second movement of 45m [E60N] needs to be split using trig.
x = 45cos60 = 22.5m
y = 45sin60 = 39.0m
Then, we add the two x and two y displacements to get the total displacement in each direction.
x = -25m + 22.5m = -2.5m
y = 0m + 39.0m
We can use Pythagorean theorem to find the total displacement.
d² = x² + y²
d = √(-2.5² + 39²)
d = 39.08m
And then we can use tan to find the angle.
inversetan(y/x) = angle
inversetan(39/2.5) = 86.3
Therefore, the total displacement is 39.08m [W86.3N]
Answer:
1. They all accelerate at the same rate.
2.The object travels at a constant velocity throughout the fall.
Explanation:
Earths gravitational pull is at a constant 9.08 m/s^2. so when objects are free falling, the objects in question can only fall so fast before it would break gravity so to speak.
Answer:
Photosynthesis
Light energy from the sun stimulates photosynthesis by green plants. One major component of the carbon cycle is the reduction of the carbon (IV) oxide content in the atmosphere by plants. Plants take in Carbon (IV) oxide to use during the process of making their own food. During this process light energy is absorbed by chlorophyll and is used to convert carbon (IV) oxide and water to glucose.
This glucose is used during respiration by living organisms that give out carbon (IV) oxide. The cycle continues.
You are almost there, often you are given a mass. But, here you already have a force. You just need to use:<span>W=Fd</span>Where W is work done, F is force, d is distance. Units of work will be Nm
