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nadezda [96]
3 years ago
12

Does current in Helmholtz coils flow in the same or opposite direction through each coil? Explain.

Physics
1 answer:
zhenek [66]3 years ago
5 0
To get a uniform field in the central region between the coils, current flows in the same direction in each. 
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Ohm’s law describes the relationship between which quantities?
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I think its between b or c
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Which is a front in which cold air is replacing warm air at the surface?
Snezhnost [94]

Answer:

C.stationarty front

Explanation:

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A horizontal spring with spring constant of 9.80 N/m is attached to a block with a mass of 1.20 kg that sits on a frictionless s
Andreas93 [3]

Answer:

Explanation:

Given

at certain point displacement and velocity is 0.345 m and 0.54 m/s

Therefore Potential and Kinetic Energy associated is

U=\frac{1}{2}kx^2

U=\frac{1}{2}\times 9.8\times (0.345)^2

U=0.583 J

Kinetic Energy K=\frac{1}{2}mv^2

k=\frac{1}{2}\times 1.2\times (0.54)^2=0.174 J

Total Energy T=U+K=0.583+0.174=0.757 J

Total Energy is conserved hence at maximum displacement  all energy will be Potential energy

T=\frac{1}{2}kA^2

where A=maximum displacement

0.757=\frac{1}{2}\times 9.8\times A^2

0.1544=A^2

A=0.393 m

Maximum speed occurs at equilibrium Position where Potential Energy is zero

thus T=\frac{1}{2}mv^2

0.757=\frac{1}{2}\times 1.2\times v_{max}^2

v_{max}=1.123 m/s

(c)When block is at 0.2 m from Equilibrium speed then its Potential Energy is

U=\frac{1}{2}kx^2=\frac{1}{2}\times 9.8\times (0.2)^2=0.196 J

T=U+K

K=0.757-0.196=0.561 J

K=\frac{1}{2}mv^2

0.561=\frac{1}{2}\times 1.2\times v^2

v=0.966 m/s

7 0
3 years ago
Instructions:Drag the tiles to the correct boxes to complete the pairs. Match each term with its definition. Tiles conductor rad
UNO [17]

<span>High SchoolPhysics5+3 pts</span><span>Instructions:Drag the tiles to the correct boxes to complete the pairs. Match each term with its definition. Tiles conductor radiation insulator convection conduction Pairs heat transfer involving direct contact of particles arrowBoth heat transfer in fluids arrowBoth heat transfer that doesn’t need a medium arrowBoth substance that doesn’t allow heat through arrowBoth substance that allows heat through arrowBoth

These are the answers:

</span>Conductor - <span>substance that allows heat through 
</span>Radiation - <span> heat transfer that doesn’t need a medium
</span>Insulator -  <span>substance that doesn’t allow heat through 
</span>Convection - <span>heat transfer in fluids
Conduction - </span>heat transfer involving direct contact of particles 
4 0
3 years ago
Read 2 more answers
a single 1,300 jk cargo car is rolling along a train track at 2.0 m/s when 400 kg of coal is dropped vertically into it. what is
tensa zangetsu [6.8K]

Answer:

1.53 m/s

Explanation:

Given:

Mass of the car (M) = 1300 kg

Mass of the coal (m) = 400 kg

Initial velocity of the car (U) = 2 m/s

Initial velocity of the coal (u) = 0 m/s (Since it is dropped)

When the coal is dropped into the car, then they move with same final velocity.

Let the final velocity be 'v' m/s.

For a closed system, the law of conservation of momentum holds true.

So, initial momentum is equal to final momentum of the car-coal system.

Initial momentum of the car = MU=1300\times 2=2600\ Ns

Initial momentum of the coal = mu=0\ Ns

Total initial momentum is the sum of the above two momentums.

So, total initial momentum = 2600 + 0 = 2600 Ns

Now, final momentum is given as the product of combined mass and final velocity. So,

Final momentum of the system = (M+m)v=(1300+400)v=1700v

Now, from law of conservation of momentum,

Initial momentum = Final momentum

2600=1700v\\\\v=\frac{2600}{1700}\\\\v=1.53\ m/s

Therefore, the final velocity of either of the two masses is same is equal to 1.53 m/s.

4 0
3 years ago
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