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nadezda [96]
3 years ago
12

Does current in Helmholtz coils flow in the same or opposite direction through each coil? Explain.

Physics
1 answer:
zhenek [66]3 years ago
5 0
To get a uniform field in the central region between the coils, current flows in the same direction in each. 
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How many electrons in Cu​
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Explanation: If you look on a periodic table, the atomic number is the amount of electrons it has.

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The motorcycle travels with a constant speed v0 along the path that, for a short distance, takes the form of a sine curve. Deter
Alexandra [31]

Let at any instant of time the speed is vo and the angle made by the bike with the horizontal is given

now we have

component of speed in x direction given as

v_x = v_0cos\theta

component of speed in y direction will be

v_y = v_0sin\theta

now from above two equations we can say that here

\theta = angle with the horizontal at any instant

and since here it is a sine curve so we know that

y = sin(x)

so we have slope of graph

tan\theta = \frac{dy}{dx} = cos(x)

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3 years ago
Suppose that an asteroid traveling straight toward the center of the earth were to collide with our planet at the equator and bu
vlada-n [284]

Answer:

\frac{1}{10}M

Explanation:

To apply the concept of <u>angular momentum conservation</u>, there should be no external torque before and after

As the <u>asteroid is travelling directly towards the center of the Earth</u>, after impact ,it <u>does not impose any torque on earth's rotation,</u> So angular momentum of earth is conserved

⇒I_{1} \times W_{1} =I_{2} \times W_{2}

  • I_{1} is the moment of interia of earth before impact
  • W_{1} is the angular velocity of earth about an axis passing through the center of earth before impact
  • I_{2} is moment of interia of earth and asteroid system
  • W_{2} is the angular velocity of earth and asteroid system about the same axis

let  W_{1}=W

since \text{Time period of rotation}∝\frac{1}{\text{Angular velocity}}

⇒ if time period is to increase by 25%, which is \frac{5}{4} times, the angular velocity decreases 25% which is \frac{4}{5}  times

therefore W_{1} = \frac{4}{5} \times W_{1}

I_{1}=\frac{2}{5} \times M\times R^{2}(moment of inertia of solid sphere)

where M is mass of earth

           R is radius of earth

I_{2}=\frac{2}{5} \times M\times R^{2}+M_{1}\times R^{2}

(As given asteroid is very small compared to earth, we assume it be a particle compared to earth, therefore by parallel axis theorem we find its moment of inertia with respect to axis)

where M_{1} is mass of asteroid

⇒ \frac{2}{5} \times M\times R^{2} \times W_{1}=}(\frac{2}{5} \times M\times R^{2}+ M_{1}\times R^{2})\times(\frac{4}{5} \times W_{1})

\frac{1}{2} \times M\times R^{2}= (\frac{2}{5} \times M\times R^{2}+ M_{1}\times R^{2})

M_{1}\times R^{2}= \frac{1}{10} \times M\times R^{2}

⇒M_{1}=}\frac{1}{10} \times M

3 0
3 years ago
Steam types of<br> forces in<br> nature
max2010maxim [7]

Answer:

Gravity, Weak, Electromagnetic and Strong.

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