Answer:
2.828 km
Explanation:
radius of lake, r = 2 km
Let O be the centre of the circular lake and you walk from A to A to D.
Displacement is the measure of shortest distance between two points.
According to the diagram , the displacement AD is
(By using the Pythagorean theorem)

AD = 2.828 km
thus, the displacement is 2.828 km.
It seems that you have missed the necessary options for us to answer this question so I had to look for it. Anyway, here is the answer. The revival of the atomic concept was catalyzed by the experimental observation which is Constant <span>composition in compounds. Hope this helps.</span>
Answer:
255 metres
Explanation:
The answer to thi question is actually quite simple. Since the car goes for 3.4 seconds, and it goes 75 metres every second, the answer is just 3.4 multiplied by 75 Metres.
Answer:
Part A:
to two significant figures
Part B:
to two significant figures
Part C:
to two significant figures
Explanation:
Given that :
mass of the hydrogen = 0.30 g
the molar mass of hydrogen gas molecule = 2 g/mol
we all know that:
number of moles = mass/molar mass
number of moles = 0.30 g /2 g/mol
number of moles = 0.15 mol
For low temperature between the range of 50 K to 100 K, the specific heat at constant volume for a diatomic gas molecule = 
For Part A:




to two significant figures
Part B. For hot temperature, 




to two significant figures
Part C. For an extremely hot temperature, 




to two significant figures