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Oksana_A [137]
3 years ago
5

A simple random sample of 13 four-cylinder cars is obtained, and the braking distances are measured. The mean braking distance i

s 137.5 ft and the standard deviation is 5.8 ft. A simple random sample of 12 six-cylinder cars is obtained, and the braking distances have a mean of 136.3 ft with a standard deviation is 9.7 ft. Use a 0.05 significance level to test thee claim that the mean braking distance of four-cylinder cars is greater than the mean braking distance of six-cylinder cars.
(a) CLAIM: IN WORDs
( b) CLAIM: IN EQUATION FORM
(c) DETERMINE THE HYPOTHESES.
(d) DRAW THE DISTRIBUTION -LABEL THE CRITICAL VALUE(S).
( e) CALCULATE THE TEST STATISTIC and include the test statistic on the graph above.
(f)STATE YOUR CONCLUSION IN CONTEXT OF H g.
(g)STATE YOUR CONCLUSION IN CONTEXT OF THE CLAIM.
Mathematics
1 answer:
Tanya [424]3 years ago
4 0
G shshshusuj bshshsu. Haha yah
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tekilochka [14]
The probability is 4/26 since MATH has 4 letters. It might be a trick question though because you're putting the card back in the hat, therefore it might be different. Sorry if this is too confusing I overthink it lol
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VERY EASY, WILL GIVE 50 POINTS FOR CORRECT ANSWER ASAP AND WILL GIVE BRAINLIEST.
Mashutka [201]

Answer:

(80, 120)

Step-by-step explanation:

y - 40 + y = 200

2y = 240

y = 120

x = 120 - 40

x = 80

Hope it helped

7 0
3 years ago
Solve for the missing angles
stich3 [128]

Answer:

x = 90°

y = 90°

Step-by-step explanation:

The angle indicated with a box shape is a right angle = 90°

Thus:

x corresponds to 90°. Therefore,

x = 90°

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5 0
3 years ago
Factor f(x)=x4-x3-7x2+13x-6 completely. Then Sketch the graph
Dennis_Churaev [7]

ANSWER TO QUESTION 1


f(x)=(x-2)(x+3)(x-1)^2.



EXPLANATION


The function given to us is,


f(x)=x^4-x^3-7x^2+13x-6


According to rational roots theorem,


\pm1,\pm2,\pm3,\pm6 are possible rational zeros of  


f(x)=x^4-x^3-7x^2+13x-6.


We find out that,


f(-3)=(-3)^4-(-3)^3-7(-3)^2+13(-3)-6


f(-3)=81+27-63-39-6



f(-3)=6-6



f(-3)=0


Also




f(2)=(2)^4-(2)^3-7(2)^2+13(2)-6



f(2)=16-8-28+26-6



f(2)=6-6



f(2)=0


This implies that  


x-2 and x+3 are factors of



f(x)=x^4-x^3-7x^2+13x-6 and hence (x-2)(x+3)=x^2+x-6 is also a factor.



We perform the long division as shown in the diagram.



Hence,


f(x)=(x-2)(x+3)(x-1)^2.


ANSWER TO QUESTION 2

Sketching the graph

We can see from the factorization that the roots  

x=2 and x=-3 have a multiplicity of 1, which is odd. This means that the graph crosses the x-axis at this intercepts.


Also the root x=1 has a multiplicity of 2, which is even. This means the graph does not cross the x-axis at this intercept.



Now we determine the position of the graph on the following intervals,


x\le -3


f(-4)=(-4)^4-(-4)^3-7(-4)^2+13(-4)-6


f(-4)=150\:>0



-3\le x \le 1


f(0)=-6\:


1\le x\le 2


f(1.5)=-0.56\:



x \ge 2



f(3)=24\:>0



We can now use these information to sketch the function as shown in diagram



4 0
3 years ago
.2x+.04x=4.8 solve for x
goblinko [34]

Answer:

x=115

Step-by-step explanation:

You substract .2 from 4.8 which is 4.6 then you divide 4.8 by .04 which is 115

6 0
3 years ago
Read 2 more answers
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