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-BARSIC- [3]
3 years ago
14

Clare estimates that her brother is 4 feet tall. When they get measured at the doctor’s office, her brother’s actual height is 4

feet, 2 inches.
What was the error, expressed in inches?

What was the error, expressed as a percentage of the actual height?
Mathematics
1 answer:
attashe74 [19]3 years ago
4 0

Her error in terms of inches was 2 inches while her percent error was 4.166%

Step-by-step explanation:

Step 1; From the given data Claire estimated her brother to be shorter than he actually was. She estimated his height to be 4 feet while it was actually 4 feet 2 inches.

We convert the feet into inches because 12 inches are equal to a feet.

4 feet = 4 × 12 inches = 48 inches

4 feet 2 inches = (4 × 12 inches) + 2 inches = 48 + 2 = 50 inches

Error in terms of inches = 50 inches - 48 inches = 2 inches.

Step 2 ; Her percent error is given by dividing the difference in values by the actual value multiplied by 100.

% error = (difference in values / actual value) × 100

Claire's % error = (50 - 48)/ 48 × 100 = 2/48 × 100 = 0.04166 × 100 = 4.166%.

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t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{-0.714 -0}{\frac{1.38}{\sqrt{7}}}=-1.369

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Step-by-step explanation:

We have the following info given by the problem

Subject  1 2 3 4 5 6 7

Drug A  6 3 4 5 7 1 4

Drug B  5 1 5 5 5 2 2

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y: 5 1 5 5 5 2 2

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And now we can calculate the statistic given by :

t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{-0.714 -0}{\frac{1.38}{\sqrt{7}}}=-1.369

Now we can find the degrees of freedom given by:

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We can calculate the p value, since we have a two tailed test the p value is given by:

p_v =2*P(t_{(6)}

We see that the p value is higher than the ususal significance levels commonly used of 1% or 5% so then we can conclude that we FAIL to reject the null hypothesis, and there is not enough evidence to conclude that we have a different response between the two drugs

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