Answer:
https://www.chegg.com/homework-help/questions-and-answers/investigate-effect-four-treatments-change-body-fat-mass-74-male-subjects-age-65-assigned-r-q21229909
Step-by-step explanation:
just go to this link and it show you the answers
Answer:
a)
Mean = sum of all numbers in dataset / total number in dataset
Mean = 8130/15 = 542
Median:
The median is also the number that is halfway into the set.
For median, we need to sort the data and then find the middle number which in our case is 546. Below is the sorted data
486 516 523 523 529 534 538 546 548 551 552 558 566 574 586
Standard Deviation (SD). Here X represents dataset and N= count of numbers in data
As per the SD formula, which is Sqrt ( sum (X_i - Meanx(X))/(N-1))
SD= 25.082
2) Formula for coefficient of skewness using Pearson's method (using median) is,
SK = 3* ( Mean (X) - Median(X))/(Standard Deviation) = 3*(542-546)/25.082 = -0.325
3) coefficient of skewness using the software method is also same which is -0.325
Answer:
should be 41.5 lbs
Step-by-step explanation:
multiply 8.3 by 5
8.3×5= 41.5
Answer:
y=-x-7
Step-by-step explanation:
Read Fiss's answer, they did it correctly
Answer:
The population increased by 34.69% over 20 years.
Step-by-step explanation:
It is given that the population of dolphins increases at a constant rate of 1.5% every year for 20 years.
Formula for population increase:
![P=a(1+r)^t](https://tex.z-dn.net/?f=P%3Da%281%2Br%29%5Et)
where, a is initial population, r is growth rate and t is time in years.
If the population of dolphins increases at a constant rate of 1.5% every year for 20 years, then the population after 20 years is
![P=a(1+0.015)^{20}](https://tex.z-dn.net/?f=P%3Da%281%2B0.015%29%5E%7B20%7D)
![P=a(1.015)^{20}](https://tex.z-dn.net/?f=P%3Da%281.015%29%5E%7B20%7D)
![P=1.346855a](https://tex.z-dn.net/?f=P%3D1.346855a)
Where, a is the initial population.
The total percentage increase over the 20 years is
![\% change=\frac{P-a}{a}\times 100](https://tex.z-dn.net/?f=%5C%25%20change%3D%5Cfrac%7BP-a%7D%7Ba%7D%5Ctimes%20100)
where, P is population after 20 years and a is initial amount.
![\% change=\frac{1.346855a-a}{a}\times 100](https://tex.z-dn.net/?f=%5C%25%20change%3D%5Cfrac%7B1.346855a-a%7D%7Ba%7D%5Ctimes%20100)
![\% change=\frac{0.346855a}{a}\times 100](https://tex.z-dn.net/?f=%5C%25%20change%3D%5Cfrac%7B0.346855a%7D%7Ba%7D%5Ctimes%20100)
![\% change=0.346855\times 100](https://tex.z-dn.net/?f=%5C%25%20change%3D0.346855%5Ctimes%20100)
![\% change=34.6855](https://tex.z-dn.net/?f=%5C%25%20change%3D34.6855)
![\% change\approx 34.69](https://tex.z-dn.net/?f=%5C%25%20change%5Capprox%2034.69)
Therefore the population increased by 34.69% over 20 years.