Answer:
Step-by-step explanation:
Perimeter of rectangle = 208 m
2*(l + w) = 208 {divide both sides by 2}
l +w = 208/2
l +w = 104
l = 104 - w
Area of rectangle = 2415 square meters
l*w = 2415
Substitute l = 104 - w in the above equation,
(104 - w ) *w = 2415
104w - w² = 2415
0 = 2415 - 104w + w²
w² - 104w + 2415 = 0
Sum = -104
Product = 2415
Factors = (-69) , (-35)
w² - 35w - 69w + (-69)*(-35) = 0
w(w - 35) - 69(w - 35) = 0
(w -35)(w -69)
w - 35 = 0 ; w -69 = 0
w = 35 ; w = 69
The dimensions of the building: 35 , 69
Answer:
1382.3 cm²
Step-by-step explanation:
We'll assume that we have to find the total surface area, including the areas of the ends.
The area of the side is given by A = 2πr·h and that of each of the ends by A = πr².
Thus, the side area is A = 2π·(10 cm)·(12 cm) = 240π cm² ≅ 754.0 cm²
and double the area of the base is A = 2·π·(10 cm)² = 628.3 cm²
and so the total surface area of the can (including the ends) is 1382.3 cm²
Well, first we have to plug in g(x) into f(x). This gets us f(g(x)) = 2(3x + 1) + 1. Then, we simply distribute and add the 1. This gets us an answer of f(g(x)) = 6x + 3.
Hope this helps!
Answer:
Look at the image I included
Answer:
perimeter of quadrant circle=1/4×pi×radius
""""" =1/4×3.14×10
perimeter of quadrant circle= 7.85cm
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