Set Events:
T=tests positive~T=tests negativeP=subject is pregnant~P=subject is not pregnant
We are givenP(T n ~P)=0.02P(~T n P)=0.03P(P)=0.7
recall by definition of conditional probabilityP(A|B)=P(A n B)/P(B)
Need to find P(P|~T)
First step: make a contingency diagram of probabilities (intersection, n)
P ~P sum
T 0.67 0.02 0.69=P(T)
~T 0.03 0.28 0.31=P(~T)
sum 0.70 0.30 1.00
=P(P) =P(~P)
therefore
P(P|~T)=P(P n ~T)/P(~T)=0.03/0.31 [ both read off the contingency table ]
=0.0968
Answer:
56°, 84°, 40°
Step-by-step explanation:
The three angles of triangles have measures of 56°, (2x + 4)º, and xº.
We need to find the measures of the three angles of the triangle.
We know that, the sum of angles of triangle is equal to 180º. Using this property we get :
56°+ (2x + 4)º + xº =180º
Solving for x.
60 + 3x = 180
3x = 120
x = 40º
Other angle, = 2x+4
= 2(40)+4
= 80+4
= 84º
So, the measures of the three angles of the triangle are 56°, 84°, 40°. Hence, the correct option is (c).
B Beacuse b best fits the situation
The answer is 6 btw it’s wrong!
