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3 years ago

Answer quick please.

Mathematics

1 answer:

attashe74 [19]3 years ago

7 0

Answer:

52 cm²

Step-by-step explanation:

A=2(wl+hl+hw)=2·(2·3+4·3+4·2)=52

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A particle moves on a straight line and has acceleration a(t)=24t+2. Its position at time t=0 is s(0)=3 and its velocity at time

user100 [1]

Answer:

It's position at time t = 5 is 593.

Step-by-step explanation:

The velocity v(t) is the integral of the acceleration a(t)

The position s(t) is the integral of the velocity v(t)

We have that:

The acceleration is:

$a(t) = 24t + 2$

Velocity:

$v(t) = \int {a(t)} \, dt = \int {24t + 2} \, dt = 12t^{2} + 2t + K$

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13

Then

$v(t) = 12t^{2} + 2t + 13$

Position:

$s(t) = \int {s(t)} \, dt = \int {12t^{2} + 2t + 13} \, dt = 4t^{3} + t^{2} + 13t + K$

Since s(0) = 3

$s(t) = 4t^{3} + t^{2} + 13t + 3$

What is its position at time t=5?

This is s(5).

$s(t) = 4t^{3} + t^{2} + 13t + 3$

$s(5) = 4*5^{3} + 5^{2} + 13*5 + 3$

$s(5) = 593$

It's position at time t = 5 is 593.

3 0

3 years ago

Solve for j.<br> 2j - k= 5

Andreas93 [3]

Answer:

j=1/2k+5/2

Step-by-step explanation:

2j−k=5

Step 1: Add k to both sides.

2j−k+k=5+k

2j=k+5

Step 2: Divide both sides by 2.

2j/2=k+5/2

j=1/2k+5/2

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3 years ago

0.008 is 1 tenth of what decimal

shepuryov [24]

0.08, Hope it helped

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FIRST BRAINIEST Tifania and Sean tried to find the circumference of a circle with a radius of 14 cm. Their work is shown below.

Simora [160]

Tifania’s work is correct because the formula for circumference is 2(3.14)(r)

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3 years ago

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Thepotemich [5.8K]

Answer:

okay

Step-by-step explanation:

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