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wel
3 years ago
9

11) When salt and water are mixed, they form a solution like in the ocean. When sand and water are mixed, they form a mixture wh

ere the sand does not dissolve. Which statement might summarize this observation? A) Mixtures and solutions are the same. B) All substances mixed with water are solutions. C) In mixtures, you cannot see the separate substances. D) In solutions you cannot see the separate substances.
Chemistry
1 answer:
mihalych1998 [28]3 years ago
5 0

Answer: D

Explanation:

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Hess’s Law can be used to determine the heat of reaction in the lab. True False
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I think it's false I'm just guessing
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3 years ago
Part a use these data to calculate the heat of hydrogenation of buta-1,3-diene to butane. c4h6(g)+2h2(g)→c4h10(g)
Reptile [31]

<u>Answer:</u> The heat of hydrogenation of the reaction is coming out to be 234.2 kJ.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H

The equation used to calculate enthalpy change is of a reaction is:

\Delta H_{rxn}=\sum [n\times \Delta H_{(product)}]-\sum [n\times \Delta H_{(reactant)}]

For the given chemical reaction:

C_4H_6(g)+2H_2(g)\rightarrow C_4H_{10}(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(1\times \Delta H_{(C_4H_{10})})]-[(1\times \Delta H_{(C_4H_6)})+(2\times \Delta H_{(H_2)})]

We are given:

\Delta H_{(C_4H_{10})}=-2877.6kJ/mol\\\Delta H_{(C_4H_6)}=-2540.2kJ/mol\\\Delta H_{(H_2)}=-285.8kJ/mol

Putting values in above equation, we get:

\Delta H_{rxn}=[(1\times (-2877.6))]-[(1\times (-2540.2))+(2\times (-285.8))]\\\\\Delta H_{rxn}=234.2J

Hence, the heat of hydrogenation of the reaction is coming out to be 234.2 kJ.

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3 years ago
Consider the group a1 element sodium atomic number 11, the group 3a element aluminum atomic number 13, and the group 7a element
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According to there chemical properties
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Are two atoms of the same element identical??​
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3 years ago
The theoretical yield for a reaction is 55.9 g LiCl. The actual yield is 24.6 g LiCl. What is the percent yield of the reaction?
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In chemical reactions, the actual yield is not the same as the expected yield . Actual yield is lower than the theoretical yield . Then we have to find the yield percentage. To see what percentage of the theoretical yield is the actual yield.
Percent yield = actual yield / theoretical yield x 100%
Percent yield = 24.6/55.9 x100%
Percent yield = 44%
7 0
3 years ago
Read 2 more answers
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