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ira [324]
3 years ago
5

Which one of the following compounds will NOT be soluble in water? Which one of the following compounds will NOT be soluble in w

ater? LiOH BaSO4 NaNO3 MgCl2 K2S
Chemistry
1 answer:
Nadusha1986 [10]3 years ago
5 0

Answer:

BaSO_{4} will be not soluble in water

Explanation:

LiOH is a strong base. Hence it gets completely dissociated in aqueous solution.

NaNO_{3} is a strong electrolyte. Hence it gets completely dissociated in aqueous solution.

MgCl_{2} is a strong electrolyte. Hence it gets completely dissociated in aqueous solution.

K_{2}S is a strong electrolyte. Hence it gets completely dissociated in aqueous solution.

BaSO_{4} is a sparingly soluble salt. Hence it is not dissociated and hence dissolved in water. This is due to the fact that both Ba^{2+} and SO_{4}^{2-} ions are similar in size. Hence crystal structure of BaSO_{4} is quite stable. Hence BaSO_{4} is reluctant to undergo any dissociation in aqueous solution.

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Answer:

pOH = 1.3, pH = 12.7

Explanation:

Since NaOH is a strong base, it will completely ionize; further, since it completely ionizes, our hydroxide concentration (a product of the ionization) will be the same as the given concentration of NaOH.

NaOH -> Na⁺ + OH⁻, [OH⁻] = 5.0 x 10^-2 M

pOH is the negative log of the hydroxide concentration, so plug our hydroxide concentration in:

pOH = -log[OH⁻] = -log[5.0 x 10^-2 M] = 1.3

Since pH + pOH = 14, we can plug in pOH and solve for pH:

pH + 1.3 = 14

pH = 14 - 1.3 = 12.7

Thus, our pOH = 1.3 and pH = 12.7.

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