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ira [324]
3 years ago
5

Which one of the following compounds will NOT be soluble in water? Which one of the following compounds will NOT be soluble in w

ater? LiOH BaSO4 NaNO3 MgCl2 K2S
Chemistry
1 answer:
Nadusha1986 [10]3 years ago
5 0

Answer:

BaSO_{4} will be not soluble in water

Explanation:

LiOH is a strong base. Hence it gets completely dissociated in aqueous solution.

NaNO_{3} is a strong electrolyte. Hence it gets completely dissociated in aqueous solution.

MgCl_{2} is a strong electrolyte. Hence it gets completely dissociated in aqueous solution.

K_{2}S is a strong electrolyte. Hence it gets completely dissociated in aqueous solution.

BaSO_{4} is a sparingly soluble salt. Hence it is not dissociated and hence dissolved in water. This is due to the fact that both Ba^{2+} and SO_{4}^{2-} ions are similar in size. Hence crystal structure of BaSO_{4} is quite stable. Hence BaSO_{4} is reluctant to undergo any dissociation in aqueous solution.

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Which item does not depend on rare earth elements?
Alisiya [41]

Answer:

Perrous magnets

Explanation:

6 0
2 years ago
What’s the most density thing out of
Oksanka [162]

Answer:

Iron is the densest out of the given options.

Explanation:

Oxygen

1.429 g/L

Water

1000 g/L

Hydrogen Peroxide

1450 g/L

Iron

7874 g/L

Iron Oxide

5240 g/L

7 0
3 years ago
When the products of a reaction have less energy than the reactants
ohaa [14]

Answer:

the energy of the products is less than the energy of the reactants.

Explanation:

the the change is enthalpy is negative, and heat is released to the surroundings.

7 0
2 years ago
Find the pH of a 0.100 molar H2C6O6 solution with ka, where KA is equal 8.0×10–5​
lubasha [3.4K]

The pH of the solution is 2.54.

Explanation:

pH is the measure of acidity of the solution and Ka is the dissociation constant. Dissociation constant is the measure of concentration of hydrogen ion donated to the solution.

The solution of C₆H₂O₆ will get dissociated as C₆HO₆ and H+ ions. So the molar concentration of 0.1 M is present at the initial stage. Lets consider that the concentration of hydrogen ion released as x and the same amount of the base ion will also be released.

So the dissociation constant Kₐ can be written as the ratio of concentration of products to the concentration of reactants. As the concentration of reactants is given as 0.1 M and the concentration of products is considered as x for both hydrogen and base ion. Then the

K_{a}=\frac{[H^{+}][HB] }{[reactant]}

[HB] is the concentration of base.

8 * 10^{-5} =\frac{x^{2}  }{0.1}\\\\\\x^{2} = 8 * 10^{-5}*0.1

x^{2} = 0.08 * 10^{-4}\\ \\x = 0.283*10^{-2}

Then

pH = - log [x] = - log [ 0.283 * 10^{-2}]\\ \\pH = 2 + 0.548 = 2.54

So the pH of the solution is 2.54.

4 0
2 years ago
Identify the conjugate acid/base pairs in each of the following equations:
Valentin [98]

Answer:

(a) Pair 1: H₂S and HS⁻

    Pair 2: NH₃ and NH₄⁺

(b) Pair 1: HSO₄⁻ and SO₄⁻

    Pair 2: NH₃ and NH₄⁺

(c) Pair 1: HBr and Br⁻

    Pair 2: CH₃O⁻ and CH₃OH

(d)  Pair 1: HNO₃ and NO₃⁻

     Pair 2: H₃O⁺

Explanation:

When an acid loses its proton (H⁺), a conjugate base is produced.

When a base accepts a proton (H⁺), it forms a conjugate acid.

(a) H₂S is an acid. When it loses a proton, it forms the conjugate base HS⁻.

    NH₃ is a base. When NH₃ gains a proton, it forms the conjugate acid NH₄⁺

(b) The acid HSO₄⁻ loses a H⁺ ion and forms the conjugate base SO₄²⁻.

     The base NH₃ accepts a H⁺ ion to form the conjugate acid NH₄⁺.

(c) HBr is an acid. When loses the H⁺ ion, it forms the conjugate base Br⁻.

   CH₃O⁻ accepts a H⁺ ion to form the conjugate acid CH₃OH.

(d) HNO₃ loses a proton to form the conjugate base NO₃⁻.

    H₂O gains a proton to form the conjugate acid H₃O⁺.

6 0
3 years ago
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