All categories

3 years ago

Question is attached answer asap. Will give brainliest

Mathematics

1 answer:

schepotkina [342]3 years ago

6 0

1.) (-2,3)
2.) a=175/43 b= -70/43
3.)(7,3)

I believe i am right
I haven't one this in a long time
If i am can i get Brainliest

You might be interested in

Draw the graph of the equation: 2(x - y) + 3y =4 pls Idk how to graph it:( helppp

Karolina [17]

Answer:

i screenshoted the graph and equation in attached pic.

Step-by-step explanation:

5 0

3 years ago

Can someone help me?

AveGali [126]

A=-112 bcs -216 ft is down from sea level and -104 is also down from sea level bcs both values are in minus but -104 is higher than other so you can minus it from -216 the difference is the answer
b=-109

4 0

3 years ago

Solve on the interval [0/2pi] 1-cos(theta) = (1/2)

Airida [17]

Answer:

Final answer is $x=\frac{\pi}{3}$ and $x=\frac{5\pi}{3}$ .

Step-by-step explanation:

Given equation is $1-\cos\left(\theta\right)=\frac{1}{2}$

Now we need to find the solution of $1-\cos\left(\theta\right)=\frac{1}{2}$ in given interval $[0, 2\pi ]$ .

$1-\cos\left(\theta\right)=\frac{1}{2}$

$-\cos\left(\theta\right)=\frac{1}{2}-1$

$-\cos\left(\theta\right)=-\frac{1}{2}$

$\cos\left(\theta\right)=\frac{1}{2}$

which gives $x=\frac{\pi}{3}$ and $x=\frac{5\pi}{3}$ in the given interval.

Hence final answer is $x=\frac{\pi}{3}$ and $x=\frac{5\pi}{3}$ .

6 0

2 years ago

A random sample of the costs of repair jobs at a large muffler repair shop produces a mean of $127.95. and a standard deviation

lubasha [3.4K]

Answer:

$127.95-1.685\frac{24.03}{\sqrt{40}}=121.55$

$127.95 +1.685\frac{24.03}{\sqrt{40}}=134.35$

So on this case the 90% confidence interval would be given by (121.55;134.35)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=127.95$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=24.03 represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=40-1=39$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,39)".And we see that $t_{\alpha/2}=1.685$

Now we have everything in order to replace into formula (1):

$127.95-1.685\frac{24.03}{\sqrt{40}}=121.55$

$127.95 +1.685\frac{24.03}{\sqrt{40}}=134.35$

So on this case the 90% confidence interval would be given by (121.55;134.35)

8 0

2 years ago

lan ran 24 laps in a charity run and then walked 0.2 kilometer to the presentation table the total; distance lan traveled was 29

QveST [7]

Answer:

Step-by-step explanation:

1.225km is equal to each laps

Step-by-step explanation:

Since Kristy total distance traveled = 29.6km

And Kristy ran 24 laps and later walk 0.2km. it simply implies that

Total distance traveled = distance covered running + distance covered walking

Since we know that

Total distance traveled = 29.6km

distance covered running = 24 laps

distance covered walking = 0.2km

Distance covered running in km = total distance traveled - distance covered walking

Distance covered running in km = 29.6km - 0.2km = 29.4km.

To now find the distance for each lap.

Since we have:

Distance covered running in km = 29.4km.

Distance covered running in lap = 24 laps

i.e

24 laps = 29.4km

1 lap = x

Use cross-multiple

24 laps * x = 29.4km × 1 lap

x = 29.4km / 24

x = 1.225km

Therefore

1.225km is equal to each laps.

8 0

2 years ago