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3 years ago

Which is the best estimate of the correlation coefficient for the scatter plot?

Mathematics

2 answers:

Softa [21]3 years ago

7 0

Answer:

B. 0.9

Step-by-step explanation:

Since here as the value of X axis is get increased, the value of Y axis is also increasing.

Thus, here Positive correlation is exist.

Also the slope of line is slant.

Slope is not near to horizontal, thus Correlation Coefficient will be greater than 0.5

Also, by the point we see here that the value of X is more get increased as compare to value of Y. So 1 is also not possible.

Hence the correlation coefficient for the given scatter plot is 0.9

Kipish [7]3 years ago

3 0

The best estimate for this correlation would be B) 0.9.

We can see that the number is constantly going up, which would throw out the D answer.

We can also see that for every time the x goes up 1, the y goes up a little less than one. We can see that in the ordered pairs that exist on the graph such as (3, 2), (8, 6) and (2.1, 1.9).

Since the y values are just lower than the x, the correlation would be just under one. Therefore, 0.9 is an accurate estimation.

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yuradex [85]

Answer:

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Step-by-step explanation:

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3 years ago

WILL GIVE BRAINLEST ANSWER IF ANSWERED IN THE NEXT 24 HRS Express the complex number in trigonometric form. -5i

trasher [3.6K]

Answer:

$z=5\left(\cos \left(\dfrac{3\pi}{2}\right)+i\sin \left(\dfrac{3\pi}{2}\right)\right)$

Step-by-step explanation:

If a complex number is z=a+ib, then the trigonometric form of complex number is

$z=r(\cos \theta +i\sin \theta)$

where, $r=\sqrt{a^2+b^2}$ and $\tan \theta=\dfrac{b}{a}$ , $\theta$ is called the argument of z, $0\leq \theta\leq 2\pi$ .

The given complex number is -5i.

It can be rewritten as

$z=0-5i$

Here, a=0 and b=-5. $\theta$ lies in 4th quadrant.

$r=\sqrt{0^2+(-5)^2}=5$

$\tan \theta=\dfrac{-5}{0}$

$\tan \theta=\infty$

$\theta=2\pi -\dfrac{\pi}{2}$ $[\because \text{In 4th quadrant }\theta=2\pi-\theta]$

$\theta=\dfrac{3\pi}{2}$

So, the trigonometric form is

$z=5\left(\cos \left(\dfrac{3\pi}{2}\right)+i\sin \left(\dfrac{3\pi}{2}\right)\right)$

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