The number of cars that sold on the third week is (P3=26)
The number of cars that sold on the first week is (P4=33)
<u>Step-by-step explanation:</u>
<u>Given:</u>
- The number of cars that sold on the first week is (P0=7)
- The number of cars that sold on the second week is (P0=12)
We have to find the number of cars being sold on the upcoming week
From the data given above, frame the equation
Pn = Pn −1+7 ( 12-5=7 it denotes the cars sold in the first and the second week)
Pn=5+7n (cars in the first week and the cars sold in the second week into "n" n is used to find the cars sold in the upcoming weeks)
(If n=3)
Pn=5+7(3)
Pn=26
The number of cars that sold on the third week is (P3=26)
(If n=4)
Pn=5+7(4)
Pn=33
The number of cars that sold on the first week is (P4=33)
Answer:
C = 5.
Step-by-step explanation:
First, you need to remember that:
For the function:
h(x) = Sinh(k*x)
We have:
h'(x) = k*Cosh(k*x)
and for the Cosh function:
g(x) = Cosh(k*x)
g'(x) = k*Cosh(k*x).
Now let's go to our problem:
We have f(x) = A*cosh(C*x) + B*Sinh(C*x)
We want to find the value of C such that:
f''(x) = 25*f(x)
So let's derive f(x):
f'(x) = A*C*Sinh(C*x) + B*C*Cosh(C*x)
and again:
f''(x) = A*C*C*Cosh(C*x) + B*C*C*Sinh(C*x)
f''(x) = C^2*(A*cosh(C*x) + B*Sinh(C*x)) = C^2*f(x)
And we wanted to get:
f''(x) = 25*f(x) = C^2*f(x)
then:
25 = C^2
√25 = C
And because we know that C > 0, we take the positive solution of the square root, then:
C = 5
Answer:
6,7
Step-by-step explanation:
