V^2 = u^2 + 2gr, where v - speed, u - initial speed=0, r - displacement (or height)
v^2 = 0 + 2*10*5.4
v = 10.2 m/s
Something that goes round in circles could have a high speed but zero average velocity.
R = 2700 ohm
I = 2.4 mA = 2.4 × 10^(-3) A
I = Q/t
Q = I × t = 2.4 × 10^(-3) × 15 s = 36 C
Answer:
The acceleration of the player is - 4.9 m/s²
Explanation:
The given is:
1. The mass of the player is 55 kg
2. His initial speed is 4.6 m/s
3. The coefficient of the kinetic fraction between the player and the
ground is 0.50
We need to find the player acceleration
According to Newton's Law
→ ∑ forces in direction of motion = mass × acceleration
There is only the friction force opposite to the motion
→ Friction force = μR
where μ is the coefficient of friction and R is the normal reaction
→ The normal reaction R = mg
where m is the mass and g is the acceleration of gravity
→ m = 55 kg , g = 9.8 m/s²
→ R = 55 × 9.8 = 539 N
→ ∑ F = - μR
→ - μR = m × a
→ μ = 0.5 , R = 539 N , m = 55
→ -(0.5)(539) = 55 × a
→ - 269.5 = 55 a
Divide both sides by 55
→ a = - 4.9 m/s²
The acceleration of the player is - 4.9 m/s²
Learn more:
You can learn more about Newton's law in brainly.com/question/11911194
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Answer: f = -12 cm
Explanation: <u>Combined</u> <u>lenses</u> is an array of simple lenses with a common axis. The combination is useful for correction of optical aberrations which cannot be corrected by simple lenses.
When two lenses are in contact and are thin, focal lengths are related as:
If there is a distance between the lenses, the focal length will be:
Since the lenses in the question above are thin and in contact, the focal length of one of them will be:
-12
The focal length of the other lens is -12 cm, with the negative sign meaning it's a converging lens.
