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3 years ago

Explain how the density of a gas is different from the density of a liquid.

Physics

1 answer:

zavuch27 [327]3 years ago

7 0

Answer

The same number of particles in a gas spread further apart than in the liquid or solid states.

Explanation:

The same number of particles in a gas spread further apart than in the liquid or solid states. The same mass takes up a bigger volume. This means the gas is less dense. Density also depends on the material.

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A wave transfers _____ from the source outward in the direction of wave motion.

DerKrebs [107]

A wave transfers energy from the source outward in the direction of wave motion.

To add, in physics, a wave is an oscillation accompanied by a transfer of energy that travels through a medium (space or mass). Frequency refers to the addition of time.

5 0

3 years ago

We are sending a 30 Mbit file from source host A to destination host B. All links in the path between source and destination hav

Dmitrij [34]

Answer:

$t=1.5\times 10^{-4}\ s$

Explanation:

Given:

file size to be transmitted, $D=30\ Mb$

transmission rate of data, $\dot D=10\ Mb.s^{-1}$

propagation speed, $v=2\times 10^8\ m.s^{-1}$

distance of data transfer, $s=10000\ km=10^4\ m$

Now the delay in data transfer from source to destination for each 10 Mb:

$t'=\frac{s}{v}$

$t'=\frac{10^4}{2\times 10^8}$

$t'=5\times 10^{-5}\ s$

Now this time is taken for each 10 Mb of data transfer and we have 30 Mb to transfer:

So,

$t=3\times t'$

$t=3\times 5\times 10^{-5}$

$t=1.5\times 10^{-4}\ s$

3 0

4 years ago

Which question asks for an opinion?

blsea [12.9K]

Answer:

Explanation:

It says is it a good idea the person so 1 person can say no and the other one can say yes so it is asks for a opinion

5 0

4 years ago

A force of 5 N is applied to the end of a lever that has a length

Klio2033 [76]

Answer:

The answer is 10Nm

Explanation: I ended up just messing around with the numbers, I multiplied 5 and 2 got 10 as my answer and it was right.

4 0

3 years ago

After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 55.0 cmcm. She finds that the pen

Art [367]

Hi there!

First, let's find the period of the pendulum. This can be found by solving for the amount of time it takes for the pendulum to make ONE complete swing.

$T = \frac{\text{Total time}}{\text{Number of complete swings} }\\\\T = \frac{145}{110} = 1.318 s$

Now, let's use the equation for the period of a simple pendulum:
$T = 2\pi \sqrt{\frac{L}{g}}$

T = Period (1.318 s)
L = length of string (0.55 m)

g = acceleration due to gravity on planet (? m/s²)

Let's solve for 'g' doing some quick rearranging of the equation:
$T^2 = 4 \pi^2 (\frac{L}{g})\\\\g = \frac{4\pi^2 L}{T^2}\\\\$

Solving for 'g' by plugging in values:
$g = \frac{4\pi^2 (0.55)}{(1.318)^2}\\ \\= \boxed{12.496 \frac{m}{s^2}}$

3 0

2 years ago